Calculating Triangle Area: S1, S2 and ABF

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The discussion centers on calculating the area of triangle ABC, given the areas of triangles ABF (S1) and FGC (S2), with line AB parallel to line FG. One participant proposed a formula for the area of triangle ABC as S = S2/2 + S1 + √(S2²/4 + S1*S2), expressing uncertainty about its accuracy. Another participant confirmed that their own calculation matched this formula, suggesting it is likely correct. The conversation emphasizes the relationship between the areas of the smaller triangles and the larger triangle ABC. Overall, the participants are collaboratively seeking to validate the formula for triangle area calculation.
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Triangle Area

Hello!
I came across this: On the picture there is triangle ABC with the unknown area S. All we know is, that area of triangle ABF is S1 and area of FGC is S2. And line AB is parallel with line FG. What is the area of triangle ABC? Thanks for your help!

Im sorry for title of this thread: Triangle volume, I wanted to say "area"(a^2).

And now, I will write what I managed to get:
S=\frac{S_2}{2}+S_1+\sqrt{\frac{S_2^2}{4}+S_1 S_2 }
but, I'm not sure if its right and I don't like the way I got it, could you please tell me what was your way?
 

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Semo727 said:
Hello!
I came across this: On the picture there is triangle ABC with the unknown area S. All we know is, that area of triangle ABF is S1 and area of FGC is S2. And line AB is parallel with line FG. What is the area of triangle ABC? Thanks for your help!

Im sorry for title of this thread: Triangle volume, I wanted to say "area"(a^2).

And now, I will write what I managed to get:
S=\frac{S_2}{2}+S_1+\sqrt{\frac{S_2^2}{4}+S_1 S_2 }
but, I'm not sure if its right and I don't like the way I got it, could you please tell me what was your way?

I don't know how you got it, but my answer is the same, so at least you know it's correct. :smile:

-Dan
 
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