Calculating Tx and Inertia at Break and After Break | Simple Physics Formulas

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Discussion Overview

The discussion revolves around calculating tension and inertia in a cable system at the moment of breakage and after it breaks. Participants explore the physics involved in the dynamics of a snapped cable, including the effects of tension, acceleration, and distance traveled post-break. The conversation includes theoretical considerations and relevant equations.

Discussion Character

  • Technical explanation
  • Homework-related
  • Debate/contested

Main Points Raised

  • One participant presents formulas for tension (Tx) and acceleration (a) at break, as well as inertia calculations after breakage.
  • Another participant questions the relevance of the speed of sound in the cable to the dynamics after the snap.
  • Some participants suggest that the distance from the winch at which the cable snaps is theoretically flexible and not dependent on specific parameters.
  • A later reply raises the issue of how quickly tension goes to zero and connects this to the speed of sound in the rope.
  • One participant emphasizes the need for clarity in definitions of terms used in the equations, such as "I" and "L".
  • Another participant questions what stops the accelerated cable end after it snaps, suggesting a need for further exploration of the scenario.

Areas of Agreement / Disagreement

Participants express differing views on the significance of the speed of sound in the cable and the implications of the cable snapping. There is no consensus on the relevance of these factors or the specifics of the calculations presented.

Contextual Notes

Participants have not fully defined all variables and terms used in their equations, leading to potential misunderstandings. The discussion includes unresolved aspects regarding the dynamics of the cable after it breaks.

MarcoClement
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Homework Statement
Work out the speed at what a cable attached to a winch will move if it snaps(meaning the tension force exceed the tensile strength ).Work out as well the distance the rope will travel after it breaks.
Relevant Equations
F=ma
I=mr^2
At break
Tx=ma
a(initial)=Tx/pi.r^2.density

After break
Ix=m/12.(3r^2+h^2)
Iy=same as above
Iz=mr^2/2T(inertia)=Iz/a=mr^2/a=0at 1 second
delta L=v(initial).delta t+1/2at^2
=1/2a(1)^2
=a/2T(inertia)=[(a/2)(pi.r^2)(density)r^2]/a
=(pi.r^4.density)/2
T(inertia)=ma
a=(pi.r^4.density)/2 multiply by 1/pi.r^2.(a(initial)/2)
=r^2/a(initial)
 
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Welcome to PF.
How far from the winch does the cable snap?
Does the speed of sound in the cable have anything to do with the speed of the cable after the snap?
 
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Baluncore said:
Welcome to PF.
How far from the winch does the cable snap?
Does the speed of sound in the cable have anything to do with the speed of the cable after the snap?
Any distance from the winch. Its theoretical so any distance from winch or any weight of rope or any pulling power from winch.I don't think speed of sound is necessary
 
So how quickly does the tension go to zero (I suspect that is why @Baluncore is pointing you toward the speed of sound in the rope)?
 
MarcoClement said:
Homework Statement:: Work out the speed at what a cable attached to a winch will move if it snaps(meaning the tension force exceed the tensile strength ).Work out as well the distance the rope will travel after it breaks.
Relevant Equations:: F=ma
I=mr^2

At break
Tx=ma
a(initial)=Tx/pi.r^2.density

After break
Ix=m/12.(3r^2+h^2)
Iy=same as above
Iz=mr^2/2T(inertia)=Iz/a=mr^2/a=0at 1 second
delta L=v(initial).delta t+1/2at^2
=1/2a(1)^2
=a/2T(inertia)=[(a/2)(pi.r^2)(density)r^2]/a
=(pi.r^4.density)/2
T(inertia)=ma
a=(pi.r^4.density)/2 multiply by 1/pi.r^2.(a(initial)/2)
=r^2/a(initial)

Please make it a habit to define your terms when posting your work. What is "I"? What is "L"? Yoiks.

Also, please read the LaTeX Guide link at the bottom of the Edit window so you can post your math reasonably. Thank you.
 
MarcoClement said:
Any distance from the winch.
With the winch at the origin, if the cable snaps at x, what is there to stop the accelerated cable end before it gets to -x ?
 

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