Calculating vapor pressure from Boltzmann distribution?

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SUMMARY

The discussion centers on the limitations of using the Boltzmann distribution to calculate the fraction of particles in liquid and gas states, particularly in the context of vapor pressure and equilibrium. It is established that while the Boltzmann distribution can accurately describe the fraction of particles at varying heights in an isothermal atmosphere, it fails to account for the equilibrium state of liquid and vapor phases in a container. The key distinction lies in the fact that the saturated vapor pressure allows for multiple configurations of liquid and vapor, which the Boltzmann distribution does not accommodate.

PREREQUISITES
  • Understanding of the Boltzmann distribution and its mathematical formulation
  • Knowledge of saturated vapor pressure and phase equilibrium concepts
  • Familiarity with potential energy in thermodynamic systems
  • Basic principles of isothermal atmospheres and density variations with height
NEXT STEPS
  • Research the implications of saturated vapor pressure on phase equilibrium
  • Study the application of the Boltzmann distribution in different thermodynamic contexts
  • Explore the relationship between potential energy and particle distribution in various states
  • Investigate the mathematical modeling of vapor-liquid equilibrium systems
USEFUL FOR

This discussion is beneficial for physicists, chemists, and students studying thermodynamics, particularly those interested in phase transitions and statistical mechanics.

chingel
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Why can't we use the Boltzmann distribution to calculate what fraction of particles are in the liquid and gas states?

If in liquid state the potential energy is smaller by amount ##L## per mole lets say, the using the Boltzmann distribution (##r\propto \exp(-\Delta E/RT)##) the fraction of particles in the liquid state would be $$r_l = \frac{\exp(L/RT)}{1+\exp(L/RT)}$$ and for gas $$r_g = \frac{1}{1+\exp(L/RT)}$$
However this is not true since I can actually have any amount of water and vapor in equilibrium at some given temperature, e.g. half the container full of water or only quarter full of water (the remaining is vapor), since as long as the pressure is the saturated vapor pressure it should be in equilibrium. Why doesn't the Boltzmann distribution apply in this case?

Because in a different example, to calculate how does the density of air change with height in an isothermal atmosphere, I can use the potential energy per mole ##\mu gh## and the Boltzmann distribution to get that the fraction of particles at height ##h## is proportional to ##\exp(-\mu gh/RT)##, which is correct. Why does it work here, but not in the previous case?
 

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