Calculating Velocity for Burn Patients on a Rotating Space Station

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The discussion focuses on calculating the period of rotation for a doughnut-shaped space station designed for burn patients, where patients experience a radial acceleration of 0.98 m/s², equivalent to 1/10 of Earth's gravity. The centripetal acceleration formula, a = v²/r, is used to derive the velocity, leading to the equation v = √(gR/10), resulting in a velocity of 14 m/s. The relationship between velocity and period is established, with the period calculated as 87.9 seconds. The conversation emphasizes the importance of understanding the connection between centripetal acceleration, velocity, and the period of rotation. Overall, the calculations demonstrate the feasibility of creating a suitable environment for burn patients in a rotating space station.
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consider a rotating doughnut shaped space station used to treat burn patients. the patients are located on the outer perimeter of the station at a distance of 200 meters from the axis of rotation. calculate the period of rotation that would produce a radial acceleration equal to 1/10 the acceleration due to gravity (.98 meters/second2).

this appears to me as a centripetal acceleration problem...a=v2/r, because the acceleration is directed toward the center, but how do i get my velocity? am i going in the right direction? thanks
 
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You are on the right track.
Now, you have gotten that \frac{v^{2}}{R}=\frac{g}{10}
This has only 1 unknown, v.

Secondly, how is v related to the period?
 
well, velocity is m/s. if i solve this equation i get v2=.0049/s2, which is no good!
 
What are you talking about?
You get v=\sqrt{\frac{gR}{10}}
 
which gives you a velocity of 14 m/s. however, that does not help you find the period using centripetal accelaration
 
Sure it does: What is the relation between the velocity you found and the period?
 
velocity is 14m/s and one period is 2pi...therefore the period is equal to 87.9 seconds
 
never mind that doesn't work
 
i got it..one period equals 2 pi and the lenth of arc s/r equals the circumference of the station...thanks for your help
 
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