Calculating Volume of Rotated Geometry: Algorithm or Integration?

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SUMMARY

The discussion focuses on calculating the volume of a solid of revolution formed by rotating a two-dimensional area A(x,y) around the z-axis. The primary method mentioned is the application of integration to determine the volume, specifically using the formula that states the volume is the area of the region multiplied by the distance the center of the region moves, which is expressed as area times 2π times the distance from the center to the axis of rotation. The conversation highlights that while specific algorithms exist for certain shapes, a general approach requires integration to find the center of the area being rotated.

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  • Basic concepts of circular geometry and area calculation
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tuoni
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Unfortunately my geometry is a little rusty: if I have an area A(x,y), and rotate it around axis z (yielding a symmetrical, circular body), what is the algorithm to calculate volume?

Or am I remembering incorrectly, and the algorithms were for very specific shapes?

E.g. a circular cylinder with a cone on top; viewed from the side it has a cross-sectional area A, and rotated around axis z you get volume.
 
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The only "algorithm" is "Heron's formula": the volume of a solid of revolution, that is, a two-dimensional region rotated around an axis, is the area of the region times the distance the center of the region moves. That, in turn, is the area times 2 [itex]\pi[/itex] times the distance from the center to the axis of rotation.

Of course, for a general region, finding the center requires integration. So you might as well do it as an integral to start with.
 

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