Calculating Weight on Another Planet

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An astronaut on another planet drops a 1-kg rock, which falls 2.5 meters in 1 second, prompting a question about its weight. The discussion clarifies that the force of gravity on this planet can be calculated using the formula for free fall, leading to an acceleration of -5 m/s². Consequently, the weight of the rock is determined to be 5 N, as calculated by multiplying mass by gravitational acceleration. The conversation emphasizes understanding the relationship between gravitational force on different celestial bodies. The problem is resolved with the correct application of physics principles.
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Okay I'm stuck...Here's the problem I'm dealing with:

An astronaut on another planet drops a 1-kg rock from rest and finds that it falls a vertical distance of 2.5 meters in 1 second. On this planet, the rock has a weight of:
a) 1 N b) 2 N c) 3 N d) 4 N e) 5 N

first of all which planet is "this planet?" does he want to know what it would weigh on Earth?

If the rate of free fall on Earth in 10 m/s squared, then would the force of gravity on the other planet be 1/4 of that at 2/5 m/s?

I'm not sure if I'm going in the right direction with this...how do I know what the force of gravity is on this other planet? If I know that won't I be able to relate that to 1-kg being equal to 10 N on Earth (as is 1-kg = 1.6 Newtons on the moon because of gravity being 1/6 that of Earth)?

I'm feeling totally lost...please help soon!
 
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x = x_0 + v_0 t + 1/2 a t^2
-2.5m = 1/2 a (1 s)^2, a = -5 m/s^2

F_g (aka wieght) = mg = 1kg(5 m/s^2) = 5 N
 
Aha!

Okay...I get it!

So I use d=1/2gt^2

:wink: THANK YOU!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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