Calculating Work and Mass for a Conical Mound of Height h

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The discussion focuses on calculating the work done in constructing a conical mound of height h with a total weight M. The relationship between weight density and mass is established using the formula w = 3M/(R²πh), where R is the base radius of the cone. The integral for work is derived as W = ∫ w(xR/h)²πx dx from 0 to h, with adjustments made for the radius in terms of height. The final conclusion confirms that the work done is .25hM.

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1. A great conical mound of height h is built. If the workers simply heap up uniform material found at ground level, and if the total weight of the finished mound is M, show that the work they do is .25hM

So I related weight density to mass by using volume of a cone and got [tex]w = \frac{3M}{R^{2}\pi h}[/tex].

I used "r" as the radius of dW. and I got r = xR/h (not sure if this part is right) which would make [tex]W = \int w(xR/h)^{2}\pi xdx[/tex] from 0 to h.

Where am I messing up? Thanks.
 
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If you are using r=R*(x/h) then r=0 at x=0 and r=R at x=R. So 'x' is the distance from the top of the cone. The height (distance from the bottom of the cone) is then h-x. Replace the appropriate x in your integral with the height.
 
Oh right. Thanks for your help.
 

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