Calculating Work Done by Spring at Various Positions

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SUMMARY

The discussion revolves around calculating the work done by a spring with a force scale set at Fs = 200 N. The spring constant (k) was determined to be 1428.57 N/m using the formula k = -Fs/d, where d is the displacement of 0.14 m. However, confusion arose regarding the interpretation of the problem statement, particularly the phrase "the scale is set by Fs = 200 N." Ultimately, the original poster confirmed they solved the problem, indicating that the initial calculations were correct once the wording was clarified.

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Homework Statement


The scale is set by Fs = 200 N. We release the block at x = 14.0 cm. How much work does the spring do on the block when the block moves from xi =+8.0 cm to (a)x=+7.0 cm, (b)x=-7.0 cm, (c)x=-8.0 cm, and (d)x=-11.0 cm?
xi= initial point
x= final point

Homework Equations





The Attempt at a Solution


I'm required to obtain K first before proceeding to the next step.
Fs= -kd
k= - Fs/d
= 200/0.14
= 1428.57 N/m

K= spring constant
d=distance
But the answer is wrong. May I know the reason ? Thank you.
 
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The wording of the problem is unclear. If it means that when the spring is stretched 14 cm, the force in the spring is 200 N, then your answer is correct. But what is really meant by "the scale is set by Fs = 200 N"?
 
PhanthomJay said:
The wording of the problem is unclear. If it means that when the spring is stretched 14 cm, the force in the spring is 200 N, then your answer is correct. But what is really meant by "the scale is set by Fs = 200 N"?
Thank you very much. I solved this question already. Love you.
 

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