Calculating Work, Force, and Power in Bob's Rock Throw

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Homework Help Overview

The problem involves calculating work, force, and power related to Bob throwing a rock. It includes parameters such as the mass of the rock, its speed, and the distance over which Bob applies force.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the work-energy theorem and the relationship between work and kinetic energy. There is uncertainty about how to incorporate acceleration and the correct interpretation of kinetic energy.

Discussion Status

Some participants have provided guidance on using the work-energy theorem to find the work done. There is ongoing clarification regarding the definitions and calculations involved, particularly concerning kinetic energy.

Contextual Notes

Participants note the absence of information regarding the acceleration of the rock, which complicates the calculations. There is also confusion about terminology, specifically the meaning of "E" in the context of kinetic energy.

aligass2004
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Homework Statement



Bob can throw a 620g rock with a speed of 30m/s. He moves his hand forward .8m while doing so.
a.) How much work does Bob do on the rock?
b.) How much force, assumed to be constant, does Bob apply to the rock?
c.) What is Bob's maximum power output as he throws the rock?

Homework Equations



W = Fd
P = W/t

The Attempt at a Solution



For part a, I tried using W = Fd. I assumed F would be mg, but I think that the accelerating has to be factored in there somewhere as well. I got 4.861, but it was wrong.
 
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You're not given the acceleration of the rock, however you do know its mass and its final speed so to speak. Assuming the rock accelerates from rest, we can use the work-energy theorem to find the work done on the rock. So we have:

W_{TOT} = \Delta KE

Does that help?
 
I know that for K, I would substitute 1/2m(v^2), but I don't know how to find E.
 
aligass2004 said:
I know that for K, I would substitute 1/2m(v^2), but I don't know how to find E.

I'm not sure what you mean by "E." You're asked to find work, force, and power. What are you stuck on exactly?
 
Oh, oh...KE meant change in kinetic energy. I thought it meant kinetic energy times energy...I don't know why I thought that though.
 

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