• Support PF! Buy your school textbooks, materials and every day products Here!

What is Bob's maximum power output as he throws the rock?

  • Thread starter habibclan
  • Start date
  • #1
55
0

Homework Statement


Bob can throw a 500 g rock with a speed of 30 m/s. He moves his hand forward 1.0 m while doing so.
a. How much work does Bob do on the rock?
b. How much force, assumed to be constant, does Bob apply to the rock?
c. What is Bob's maximum power output as he throws the rock?


Homework Equations


vf^2= vi^2 + 2ad
F=ma
W= F.d

P= F.v

The Attempt at a Solution



Find the acceration provided by the applied force.

vf^2= vi^2 + 2ad
30^2= 2a (1)
a= 450 m/s^2

Then find the force using newton's second law:
F=ma
F= 450 (0.5)
F= 225 N

Now calculate work using the force applied.

W= F.d
W= 225 *1= 225 J

Power= F.v= 225*30= 6750 W.

Is this the correct way to do it? my textbook doesn't have solutions to even-numbered problems and I'm not sure if my way of calculating acceleration and then using newton's second law is correct. Any help would be greatly appreciated!
 

Answers and Replies

  • #2
PhanthomJay
Science Advisor
Homework Helper
Gold Member
7,136
476
That looks just fine. You could have done it perhaps a bit quicker using work-energy methods (if you are familiar with this method), but there's always more than one way to attack a problem.
 
  • #3
55
0
That looks just fine. You could have done it perhaps a bit quicker using work-energy methods (if you are familiar with this method), but there's always more than one way to attack a problem.
We apparently covered this method but the only work-energy equation that I know is: Ki+ Ui + Wext= Kf+ Uf+ delta E (thermal). Can you please guide me on how to set it up the work-energy way because I've seen other questions in the textbooks like that but I do them different.Thanks for your help =).
 
  • #4
tiny-tim
Science Advisor
Homework Helper
25,832
249
We apparently covered this method but the only work-energy equation that I know is: Ki+ Ui + Wext= Kf+ Uf+ delta E (thermal). Can you please guide me on how to set it up the work-energy way because I've seen other questions in the textbooks like that but I do them different.Thanks for your help =).
Hi habibclan! :smile:

Just put delta E = 0.

So in this case the equation is KE = work times distance.

Try it! :smile:
 
  • #5
55
0
Hi habibclan! :smile:

Just put delta E = 0.

So in this case the equation is KE = work times distance.

Try it! :smile:
But I don't know work. I still don't get it :(.
 
  • #6
PhanthomJay
Science Advisor
Homework Helper
Gold Member
7,136
476
We apparently covered this method but the only work-energy equation that I know is: Ki+ Ui + Wext= Kf+ Uf+ delta E (thermal). Can you please guide me on how to set it up the work-energy way because I've seen other questions in the textbooks like that but I do them different.Thanks for your help =).
As tiny-tim noted, delta E =0. So using your equation, 0 + 0 + Wext = 1/2mv^2 + 0 + 0. You know v=30, and m= .5, solve for Wext (the work done by Bob on the rock). Then since Wext = Fd, solve for F.
 
  • #7
55
0
Thanks a lot tiny-tim and PhantomJay! The help is much appreciated!
 

Related Threads for: What is Bob's maximum power output as he throws the rock?

  • Last Post
Replies
3
Views
11K
  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
3
Views
19K
Replies
1
Views
7K
Replies
1
Views
2K
Replies
8
Views
5K
Top