Calculating Work with Electric Field & Charge

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SUMMARY

The discussion focuses on calculating the work done in moving a charge of 2.0 microC in a uniform electric field of intensity 4.0 x 10^5 N/C. The correct formula used is W = E*q*d*cos(theta), where W represents work, E is the electric field intensity, q is the charge, d is the distance moved, and theta is the angle with the electric field. The calculated work is 0.08 J, confirming the accuracy of the angle and formula applied in the solution.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with the concept of electric charge
  • Knowledge of trigonometric functions, specifically cosine
  • Ability to perform unit conversions (e.g., microC to C, cm to m)
NEXT STEPS
  • Review the principles of electric field calculations
  • Study the relationship between work, charge, and electric fields
  • Learn about vector components in physics
  • Explore additional examples of work done in electric fields
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Students studying physics, particularly those focusing on electromagnetism, as well as educators looking for practical examples of electric field calculations.

Soaring Crane
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Homework Statement



A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?


a.0.14 J

b.0.34 J

c.80 mJ

d.14 J

e.8.0 J


Homework Equations




See below.

The Attempt at a Solution



W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J

I just wanted to know if the angle and formula that I used are correct.

Thanks.
 
Physics news on Phys.org
Yes, it's correct.
 

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