Calculating Work with Electric Field & Charge

[Soaring Crane]

Homework Statement

A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?


a.0.14 J

b.0.34 J

c.80 mJ

d.14 J

e.8.0 J

Homework Equations

See below.

The Attempt at a Solution

W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J

I just wanted to know if the angle and formula that I used are correct.

Thanks.

 

[neutrino]

Yes, it's correct.