A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?
The Attempt at a Solution
W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J
I just wanted to know if the angle and formula that I used are correct.