- #1
Noirchat
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I'd really like some explanations please, just looking at part (a) at the moment :)
Suppose three 1.02 MeV X-ray photons are Compton scattered by single collisions with nearly stationary electrons.
Photon 1 is scattered backwards, in the direction opposite to its original path.
Photon 2 is scattered at right angles to its original path.
Photon 3 is scattered in a direction 45° away from the forward direction.
(a) Calculate the change of wavelength for each case. Show your working.
(b) Suppose instead, the original photons energies were 0.51 MeV. What effect does this have on the values calculated above? Explain very briefly.
None were given
(a) I think i use Δλ=h/mc(1-cosθ)
Photon 1:
Photon 2:
6.626 X 10^-34/9.1094x10^-31 x 3x10^8 x (1-cos90
= 0
Photon 3:
6.626 X 10^-34/9.1094x10^-31 x 3x10^8 x (1-cos45)
= 8.666x10^-13
Homework Statement
Suppose three 1.02 MeV X-ray photons are Compton scattered by single collisions with nearly stationary electrons.
Photon 1 is scattered backwards, in the direction opposite to its original path.
Photon 2 is scattered at right angles to its original path.
Photon 3 is scattered in a direction 45° away from the forward direction.
(a) Calculate the change of wavelength for each case. Show your working.
(b) Suppose instead, the original photons energies were 0.51 MeV. What effect does this have on the values calculated above? Explain very briefly.
Homework Equations
None were given
The Attempt at a Solution
(a) I think i use Δλ=h/mc(1-cosθ)
Photon 1:
Photon 2:
6.626 X 10^-34/9.1094x10^-31 x 3x10^8 x (1-cos90
= 0
Photon 3:
6.626 X 10^-34/9.1094x10^-31 x 3x10^8 x (1-cos45)
= 8.666x10^-13
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