- #1

negation

- 818

- 0

## Homework Statement

A photon of wavelength 29 pm is scattered by a stationary electron. What is the maximum possible energy loss of the photon?

(mass of electron = 9.11 × 10-31 kg, h = 6.626 × 10^-34 J · s, c = 3.00 × 10^8 m/s)

## The Attempt at a Solution

After an hour or so, I'm not getting the right answer.

29pm = 29x10

^{-11}m

E

_{i}= E

_{f}+ KE

E

_{i}- E

_{f}= ΔE = h(c/Δλ)

I set Θ = 180 and worked out

λ

_{f}= (h/m

_{e}c)(1-cosΘ) + λ

_{i}=

4.854212x10

^{-12}m

ΔE = 6.626x10

^{-34}(3x10

^{8}/4.854212x10

^{-12})

= 4.095x10

^{-14}j

to convert to eV, i divided the above by 1.6 x10

^{-16}but it doesn't give me the correct answer.