- #1
negation
- 818
- 0
Homework Statement
A photon of wavelength 29 pm is scattered by a stationary electron. What is the maximum possible energy loss of the photon?
(mass of electron = 9.11 × 10-31 kg, h = 6.626 × 10^-34 J · s, c = 3.00 × 10^8 m/s)
The Attempt at a Solution
After an hour or so, I'm not getting the right answer.
29pm = 29x10-11m
Ei = Ef + KE
Ei - Ef = ΔE = h(c/Δλ)
I set Θ = 180 and worked out
λf = (h/mec)(1-cosΘ) + λi =
4.854212x10-12m
ΔE = 6.626x10-34 (3x108/4.854212x10-12)
= 4.095x10-14 j
to convert to eV, i divided the above by 1.6 x10-16 but it doesn't give me the correct answer.