Compton effect photo scatterred

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Homework Help Overview

The problem involves the scattering of a photon with a wavelength of 29 pm by a stationary electron, focusing on determining the maximum possible energy loss of the photon. Relevant constants include the mass of the electron, Planck's constant, and the speed of light.

Discussion Character

  • Exploratory, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the energy conservation equation and the relationship between initial and final photon energies. There are attempts to calculate the change in energy using the Compton wavelength shift formula. Some participants express difficulty in arriving at the correct answer and seek clarification on the steps taken.

Discussion Status

Several participants are actively engaged in the discussion, with some sharing their calculations and expressing frustration over not obtaining the expected results. Others request detailed solutions from their peers, indicating a collaborative effort to understand the problem better.

Contextual Notes

There appears to be confusion regarding the conversion of energy units from joules to electronvolts, as noted by participants. Additionally, the problem context involves specific constants and assumptions related to the Compton effect.

negation
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Homework Statement



A photon of wavelength 29 pm is scattered by a stationary electron. What is the maximum possible energy loss of the photon?
(mass of electron = 9.11 × 10-31 kg, h = 6.626 × 10^-34 J · s, c = 3.00 × 10^8 m/s)



The Attempt at a Solution



After an hour or so, I'm not getting the right answer.

29pm = 29x10-11m

Ei = Ef + KE

Ei - Ef = ΔE = h(c/Δλ)

I set Θ = 180 and worked out

λf = (h/mec)(1-cosΘ) + λi =
4.854212x10-12m


ΔE = 6.626x10-34 (3x108/4.854212x10-12)
= 4.095x10-14 j

to convert to eV, i divided the above by 1.6 x10-16 but it doesn't give me the correct answer.
 
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negation said:

Homework Statement



A photon of wavelength 29 pm is scattered by a stationary electron. What is the maximum possible energy loss of the photon?
(mass of electron = 9.11 × 10-31 kg, h = 6.626 × 10^-34 J · s, c = 3.00 × 10^8 m/s)



The Attempt at a Solution



After an hour or so, I'm not getting the right answer.

29pm = 29x10-11m

Ei = Ef + KE

Ei - Ef = ΔE = h(c/Δλ)

I set Θ = 180 and worked out

λf = (h/mec)(1-cosΘ) + λi =
4.854212x10-12m


ΔE = 6.626x10-34 (3x108/4.854212x10-12)
= 4.095x10-14 j

to convert to eV, i divided the above by 1.6 x10-16 but it doesn't give me the correct answer.

Edit: I have it now.
 
Hi, could you post your step by step solution? I cannot seem to get the answer
 
bababong said:
Hi, could you post your step by step solution? I cannot seem to get the answer
Edit: I got it.
 

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