Calculus and Vectors - Determining Vector and Parametric Equations

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To determine the vector and parametric equations for a plane containing the point A(2, 3, -1) and parallel to a given plane, the correct approach involves adding vector A to the points of the original plane. The resulting equation is (x, y, z) = A + s(5, 2, -1) + t(3, -2, 4). It is crucial to ensure that the new plane includes point A and retains the same direction vectors as the original plane. Verification of the work is emphasized, as mathematics allows for self-checking of solutions. The discussion highlights the importance of accuracy in formulating vector equations.
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Homework Statement
Determine vector and parametric equations for the plane containing the point A(2, 3, -1) and parallel to the plane with equation (x, y, z) = (2, 1, -3) + s(5, 2, -1) + t(3, -2, 4).

Can someone confirm?
Relevant Equations
n/a
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ttpp1124 said:
Homework Statement:: Determine vector and parametric equations for the plane containing the point A(2, 3, -1) and parallel to the plane with equation (x, y, z) = (2, 1, -3) + s(5, 2, -1) + t(3, -2, 4).

Can someone confirm?
Relevant Equations:: n/a

View attachment 260205
Comment: Your vector equation isn't an equation. An equation always has '=' in it.
Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.
 
Mark44 said:
Comment: Your vector equation isn't an equation. An equation always has '=' in it.
Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.

To obtain a plane parallel to P0 and passing through the point A(2,3,−1), all we need to do is add A as a vector (I dropped the coordinates for brevity) to all the points of P0. This gives us the plane

(𝑥,𝑦,𝑧)=𝐴+𝑠(5,2,−1)+𝑡(3,−2,4)
 
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ttpp1124 said:
To obtain a plane parallel to P0 and passing through the point A(2,3,−1), all we need to do is add A as a vector (I dropped the coordinates for brevity) to all the points of P0. This gives us the plane

(𝑥,𝑦,𝑧)=𝐴+𝑠(5,2,−1)+𝑡(3,−2,4)
Yes,, I understand how you got the equation, but I was responding to your request for someone to verify that your work was correct. Here's what I said before:
Mark44 said:
Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.
One of the things I've always liked about mathematics, especially at somewhat higher levels, is that it's not difficult to verify your work for yourself. What I said above was how you can do this.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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