 #1
 110
 4
 Homework Statement
 Calculus and Vectors  Vector and Parametric Equations
I solved it, can someone concur?
 Relevant Equations
 Not Available

When I sub in 0 for t, I get the values corresponding to the direction vector. That's how I know it's correct
how is it wrong?Looks wrong to me!
Is that ##x = 2t, \ y = 1 + 3t, \ z = 6 + 5t##?how is it wrong?
YesIs that ##x = 2t, \ y = 1 + 3t, \ z = 6 + 5t##?
That's not right. What values of ##t## give you ##P## and ##Q##?Yes
Is it the direction vector, 0,1,6?That's not right. What values of ##t## give you ##P## and ##Q##?
The vector equation is correct. That's the direction ##\vec{QP}##.Is it the direction vector, 0,1,6?
Right, so I think I didn't multiply the t value and do vector addition. When I do multiply, I get r = (2,3,5)+(0t,t,6t).The vector equation is correct. That's the direction ##\vec{QP}##.
So, what value of ##t## gives you ##Q##?Right, so I think I didn't multiply the t value and do vector addition. When I do multiply, I get r = (2,3,5)+(0t,t,6t).
Then I do vector addition by components, so then my parametric equations should be 2+0t, 3t, and 5+6t
1So, what value of ##t## gives you ##Q##?
My question is, how does the value of t have anything to do with the actual question? They just wanted to know the vector and parametric equations.1
My question is, how does the value of t have anything to do with the actual question? They just wanted to know the vector and parametric equations.
Also, are my new parametric equations correct?