- #1
rshen5
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Homework Statement
Find the angles between the tangents to y=-3e^-x and y=2+e^x at their poit of intersection
Homework Equations
y=-3e^-x and y=2+e^x
The Attempt at a Solution
i tried to find the point at which they intersect:
y=-3e^-x =2+e^x
where i got
x=ln 1
then i tried to find derivative of both equations:
y'=-3e^-x
y'=e^x
then subsitute the value of x in
and got
y'=-3
y'=1
forming 2 vectors ?
a=(-3,1)
b=(1,1)
then using vector = dot point equation to find the angle between them ..
a*b*cos (theta) = a_x*b_x+a_y+b_y
but i still got the wrong answer
the answe is : 63.43 degrees