Calculus based question in my physics course. No real physics required though.

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SUMMARY

The discussion centers on the calculation of the dot product of a vector field, represented as a = xyi + y²j + 2k, with the del operator ∇ = ∂/∂x + ∂/∂y + ∂/∂z. The user initially struggled with the derivatives and the dropping of Cartesian components in the solution. Ultimately, the correct computation yields ∇ . a = 3y, confirming the user's understanding of how to apply the del operator to the vector field.

PREREQUISITES
  • Understanding of vector calculus, specifically the dot product.
  • Familiarity with the del operator (∇) and its application in fluid mechanics.
  • Knowledge of partial derivatives and their notation.
  • Basic concepts of vector fields in physics.
NEXT STEPS
  • Study the application of the del operator in various coordinate systems.
  • Learn about vector calculus identities and their implications in physics.
  • Explore fluid mechanics principles related to vector fields.
  • Practice problems involving the divergence and curl of vector fields.
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Students of physics, particularly those studying fluid mechanics, as well as anyone looking to strengthen their understanding of vector calculus and its applications in physical problems.

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Figured it out! No need to answer. Thanks!


Homework Statement


Hey all, I have a question right at the beginning of my fluid mechanics book but it mostly focuses on calculus at this point. This question in particular is all calculus.

a = xyi + y2j + 2k

∇ = ∂/∂x + ∂/∂y + ∂/∂z

What is ∇ . a [DOT PRODUCT of the two]


Homework Equations



Equations given above.


The Attempt at a Solution



I'm assuming since I'm dotting it that the ∂/∂x would be multiplied by the xyi component and so forth for the rest which would mean just do the derivative of each. For some reason the cartesian i j k get dropped in the solutions when they are dotted up. I don't really understand that. When I do the derivative of each I get:

yi + xi + 2yk

The first yi is from doing the derivative of xyi with respect to x, the second xi is from doing the derivative of xyi with respect to y, and the last 2yk is from doing y2j with respect to y.

^hopefully that made sense. The solution manual makes the dotted product drop all the cartesian parts. It goes:


∇.a = ∂ax/∂x + ∂ay/∂y + ∂az/∂z

= y + 2y + 0 = 3y

Not really sure how this works. Would appreciate any help greatly. Thanks!
 
Last edited:
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Wow never mind I just figured it out by myself a few minutes after posting this! I didn't really understand how these derivatives worked but now I understand that the ∇ = ∂/∂x + ∂/∂y + ∂/∂z also has cartesian i, j, and k and you just match that up with the original and derive accordingly. Got the same answer of 3y. Huh, not too bad! Thanks anyway.
 

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