Calculus of variation. Minimum surface

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SUMMARY

The discussion focuses on the calculus of variations, specifically addressing the derivation of the equation related to minimum surface problems. The participants analyze the expression for the functional, given by \( f = y \sqrt{1+y'^2} \), and its manipulation through multiplication by \( \frac{\sqrt{1+y'^2}}{\sqrt{1+y'^2}} \). The goal is to clarify how this manipulation leads to the desired equation, which is crucial for solving variational problems involving surfaces.

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  • Understanding of calculus of variations
  • Familiarity with differential equations
  • Knowledge of functional analysis
  • Proficiency in manipulating algebraic expressions
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  • Study the derivation of Euler-Lagrange equations in calculus of variations
  • Explore applications of minimum surface problems in physics and engineering
  • Learn about the geometric interpretation of variational principles
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Mathematicians, physicists, and engineers interested in optimization problems and the calculus of variations will benefit from this discussion.

knockout_artist
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so df/dy' is yy'/ √(1+y'^2)

then we are supposed to do
y' . [ yy'/ √(1+y'^2) ] - y√(1+y'^2)

how does this bring equation 2 in the image ?
 

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imaged rotated :)
 
Multiply ##f = y \sqrt{1+y'^2}## by ##1 = \frac{\sqrt{1+y'^2}}{\sqrt{1+y'^2}}## then subtract from ##y' f_y'##.
 
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