Calculus Problem with simplifying

AI Thread Summary
The discussion centers on a calculus problem involving differentiation and simplification of the function f(x) = (1-x)^4 / (1-4x). The user is struggling to simplify the derivative f'(x) after applying the product rule, particularly with the cancellation of terms. Participants suggest that the user cannot cancel (1-4x) from the numerator and denominator since it does not appear as a common factor. It is recommended to expand the numerator to check for divisibility by (1-4x) or to factor out (1-x)^3 to aid in simplification. Overall, the conversation emphasizes the importance of careful factorization and expansion in calculus problems.
K - Prime
Messages
6
Reaction score
0
well ill go through the whole question up to where i am (not very far) to make sure there were no prior errors, but i can't simplfy past where i am (maybe i just can't see it)

Differentiate and simplify

...(1-x)^4
f(x) = --------
...1-4x

f'(x) = [4(1-x)^3(-1)](1-4x) - (1-x)^4(-4)
...-----------------------------------
......(1-4x)^2

...= (-4)(1-x)^3 - (1-x)^4(-4)
...------------------------- note: i canceled the (1-4x) on top
.....(1-4x) with one from the bottom


...= stuck (i tried common factoring on top but still can't get it)

any help will be GREATLY appreciated (last question on assignmentand driving me crazy)

sorry bout the formating, can't seem to get it right (hence the periods)
 
Last edited:
Physics news on Phys.org
how'd you cancel out the (1-4x) from the top and bottom? (1-x)^4*-4 doesn't have (1-4x) as a common factor with the denominator. My personal suggestion (although lengthy to an extent) would be to expand all the numerator and see if it's divisible by 1-4x.
 
You can't cancel out the (1-4x) because it only appears on the left side of the numerator and not on the right. I don't see that much that's easily simplified (if you expanded the numerator so you could do the subtraction, it might simplify, but I doubt it).
 
Hrm I haven't really tried anything with it but see what happens when you factor out (1-x)^3 from the top from the left and right operands of the middle - sign.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top