Calculus question - involving trigonometry

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Homework Help Overview

The discussion revolves around a calculus problem that involves trigonometric concepts, specifically related to illumination intensity and its mathematical representation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express uncertainty about starting the problem and the meaning of certain variables. There are questions regarding the origin of specific constants, such as the number 8, and the relevance of trigonometric identities in the context of the problem.

Discussion Status

Some participants have provided guidance on how to approach the problem, suggesting that understanding the physical meaning of variables may not be necessary for solving the mathematics. There is an ongoing exploration of the relationships between the variables involved.

Contextual Notes

Participants note that the problem includes specific terms and conditions, such as the definition of "I" as illumination intensity, which may influence the approach to the mathematical solution.

rshen5
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Homework Statement


Homework Equations


The Attempt at a Solution


i have no idea how to start
 

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welcome to pf!

hi rshen5! welcome to pf! :smile:

(have a theta: θ and a square-root: √ :wink:)

show us what you've tried, and where you're stuck, and then we'll know how to help …

start with part a :smile:
 
you have any idea where the 8 came from ?
 
rshen5 said:
you have any idea where the 8 came from ?

i expect it's written in tiny print on the light bulb :biggrin:

get on with it! :rolleyes:
 
well.. i know I am completely wrong, cause i don't even know what "I" is..
 

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(you don't need to know what I is, you only need to know when it's a maximum! :rolleyes:)

why are you bothering with Pythagoras?

you've found that AN = xsinθ, and you know that AN = 1 :smile:
 
The problem tells you that "I" is the "illumination"- the intensity of the light at that point. However, as tinytim suggests, knowing the specific physical meaning of variables is not necessary to do the mathematics!
 
HallsofIvy said:
… knowing the specific physical meaning of variables is not necessary to do the mathematics!

maths is so cool! :biggrin:
 
recall from elementary trigonometry that
1+cot(t)^2=csc(t)^2
you got a little carried away
you wrote AN=x sin(theta)
also AN=1 so x=csc(theta)=1/sin(theta)
you can write I in terms of theta by substituting x=csc(theta) into I
x^2=x^2cos(theta)^2+x^2sin(theta)^2
reduces to the un helpful
x^2=x^2
not x^2=2x^2+1
 
  • #10
Thank you thank you ~~
gee that was easy.. (what was i thinking)

but does anyone know how they actually got the equation? just curious :-p
 

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