Can a 10A Fuse Handle a 150W Radio and 240V Water Heater in Parallel?

AI Thread Summary
A 10A fuse can handle the simultaneous use of a 150W radio and a 240V water heater with a resistance of 40Ω. The current drawn by the radio is calculated to be 0.625A, while the heater draws 6A. The total current required for both devices is 6.625A, which is below the 10A limit of the fuse. Therefore, the fuse will not blow under these conditions. The calculations confirm that the setup is safe for use.
chawki
Messages
504
Reaction score
0

Homework Statement


A radio (power = 150 W) and a water heater (resistance = 40 Q) are connected in
parallel. The current, needed for them is fused at 10 A maximum.

Homework Equations


Does the fuse stand the simultaneous use of the radio and the heater? The voItage is 240 V.

The Attempt at a Solution


r: radio
h: heater

V=Vr=Vh
Itotal=Ir+Ih

Pr=V*Ir
Ir=150/240=0.625 ampere

Vh=R*Ih
Ih = Vh/R = 240/40 = 6 amperes

Itotal = 0.625+6 = 6.625
6.625<10 so the fuse will stand
 
Physics news on Phys.org
That looks good.
I guess the "40Q" meant "40Ω".
 
Delphi51 said:
That looks good.
I guess the "40Q" meant "40Ω".
yesyes 40Ω , and thank you o:)
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Hot Threads

Recent Insights

Back
Top