kev said:
Your reasoning about the density is good but you appear to be locked into thinking in terms of the well known exterior Schwarzschild solution rather than the interior Schwarzschild solution that is applicable in this case.
Doesn't the Schwarzschild solution only describe the case of an eternal nonrotating black hole, rather than one that forms from a collapsing star (idealized as a uniform dust sphere)? Of course this also somewhat undermines my argument about the radius of the absolute horizon at an early moment being larger than the Schwarzschild radius for the amount of mass contained within the absolute horizon at that moment, since in this dynamic situation the Schwarzschild radius may no longer describe the point at which a collection of mass can no longer avoid collapsing to a singularity. Still, from Kip Thorne's straightforward description, and from xantox's comments, I'm still fairly certain that whether or not there's an absolute horizon at a particular point in spacetime
cannot be determined solely by events in the past light cone of that point. And I would still guess that, prior to the point where the entire collapsing dust sphere has passed the point where the "apparent horizon" would form (which I think is still the Schwarzschild radius), it would in principle be possible to blow it apart completely using non-gravitational forces and prevent any horizons from forming at all (by setting off a powerful bomb at the center, say, or by imaging the sphere to be made of a giant collection of tiny rockets, which all begin to fire away from the center at some time prior to the whole sphere shrinking to a radius smaller than the Schwarzschild radius).
kev said:
If you draw a horizontal line just after the absolute horizon forms you will find that its radius is completely determined by all the mass and its distrubution at that instant (defined by the horizontal line.
It's probably true that
if you assume no non-gravitational forces are applied and all the dust particles just follow geodesics, then with that assumption you can determine the absolute horizon's radius at any instant just based on the coordinate position of all the dust particles at that instant. But like I said, I would guess that before the whole sphere crosses the point where the apparent horizon forms, then the entire sphere can be disrupted by non-gravitational forces and this retroactively means that no absolute horizon formed at all. In contrast, once the sphere has passed the point where the apparent horizon forms (again, I think that's just the Schwarzschild radius) then no non-gravitational forces can prevent it from collapsing into a singularity.
kev said:
What is very bothersome about all this is that it does appear to give a mechanism by which information can transmitted faster than light. If a clock is placed at the centre before any event horizon has formed, an observer just outside the centre could observe the clock stop or stop seeing the clock, because it is behind an event horizon and be aware of whether the rockets had turned around or not before he/she could possiby be aware of that information by means of light speed signals.
But the absolute horizon is defined in terms of whether light from an event will
ever reach the outside. The mere fact that light from a certain tick of a clock hasn't reached you
yet doesn't prove that this event happened behind an absolute horizon, because it still might reach you at a later time. Imagine two collapsing dust spheres made out of tiny rockets, and in sphere A the rockets never fire and the entire sphere collapses to a black hole as in the diagram, while in sphere B all the rockets fire at some time t1 prior to the point when the whole sphere has crossed the radius of the apparent horizon. Suppose in sphere A, the absolute horizon begins to form at time t0. If a tick of a clock is behind this growing absolute horizon in sphere A, it will never reach the eyes of an observer outside the absolute horizon. Now, my guess is that in sphere B, in spite of the fact that the behavior of all the rockets is identical to those of sphere A prior to time t1, no absolute horizon will
ever form. Nevertheless, if a certain clock tick happens in sphere B prior to t1 at a point where it would be inside the absolute horizon of the identical sphere A, I would assume that the light from this event cannot reach any observer at a position that would be outside where the absolute horizon would be in sphere A until
after time t1 when the rockets have fired and the behavior of the two spheres has begun to diverge. So up until t1, this external observer won't see the clock tick and might be tempted to think it's behind a horizon, but then sometime after t1 he will see it and he'll realize that the light was just delayed but not permanently trapped. This is of course just my guess, I don't know enough to actually do the math to prove or disprove it, but the idea seems consistent enough and doesn't lead to any physical paradoxes.