Can a spy satellite read the house number on your mailbox?

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A spy satellite positioned 200 km above Earth can potentially read a house number on a mailbox using a concave mirror with a diameter of 2 meters and yellow light at 600 nm. The Rayleigh criterion formula, θmin = 1.22 * (Wavelength/Size of the mirror), is essential for determining the resolving power. The discussion indicates that the size of the object, rather than distance, should be used in calculations. Participants express uncertainty about having enough information to reach a definitive conclusion. Overall, the conversation emphasizes the importance of applying the correct formulas to assess the satellite's capabilities.
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If the spy satellite, which is 200km above the earth, uses a concave mirror 2m in diameter and yellow light at 600 nm find the answer. show all formulas and work to support the correct solution. with that resolving power what could the spy satellite actually see? (ignore variations in air density and temperature.)

The only formulas that I can see as being useful are: thetamin = 1.22*Wavelength/distance (Rayleigh criterion) and 1/focus =1/object+1/image

Quite frankly I don't think there is enough information to figure this out. Any help would be appreciated.
 
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Plasmosis1 said:
The only formulas that I can see as being useful are: thetamin = 1.22*Wavelength/distance (Rayleigh criterion)
"Distance" should be "size of the object" (or, alternatively, size of the mirror).
You can use that formula to calculate everything in this problem.
 
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