Can a system have a negative temperature based on its energy and entropy?

Click For Summary
SUMMARY

The discussion centers on the concept of negative temperature in thermodynamic systems, particularly in paramagnetic systems with a fixed number of particles. It is established that negative temperature can occur when certain conditions are met: the system must have bounded energy, reach internal equilibrium quickly, and be isolated from other systems. The example provided illustrates that when the majority of spins in a system are anti-parallel to an applied field, the system can exhibit negative temperature, which is "hotter than infinity" and will transfer energy to systems with positive temperature. The multiplicity function and its relation to energy and entropy changes are also explored.

PREREQUISITES
  • Understanding of thermodynamics and entropy
  • Familiarity with paramagnetic systems and spin states
  • Knowledge of statistical mechanics and multiplicity functions
  • Basic principles of energy exchange in thermodynamic systems
NEXT STEPS
  • Research the conditions for achieving negative temperature in thermodynamic systems
  • Study the implications of bounded energy in statistical mechanics
  • Examine the role of spin systems in thermodynamics, particularly in nuclear spin systems
  • Read Ramsey's 1950s article on thermodynamics with negative temperature for historical context
USEFUL FOR

Physicists, thermodynamic researchers, and students studying statistical mechanics who are interested in advanced concepts of temperature and entropy in systems with unique properties.

ak416
Messages
121
Reaction score
0
Ok i thought i had this under control, but now i come to think about it, i get more confused. I know d sigma/d U for any system must be positive because the temperature must be positive (sigma is the entropy and U is the energy). But what about this? Consider the model of the paramagnetic system where there's a constant N particles in a constant volume. The energy is proportional to how many spin down - spin up particles there is. So let's say for system 1, N= 30. 29 are spin down, 1 is spin up (Lets just say energy is 28). Let's say this system comes in thermal contact with another system (system 2). (the systems are allowed to exchange energy). So initially the entropy of the 1st system is 30 choose 1 = 30. Now let's say system 1 exchanges its spin up for spin down (Change in energy is +2). But now entropy is 30 choose 0 = 1. So change is entropy is -29. so change is entropy wrt to change in energy is negative? And temperature which is 1 over that is negative?
 
Last edited:
Physics news on Phys.org
Don't worry! As it turns out, negative temperature is a perfectly reasonable thing that has been realized in the laboratory in nuclear spin systems. Negative temperature is possible provided three conditions are met. First, the system must have bounded energy. Second, the system must be able to reach internal equilibrium quickly. Third, the system must be isolated (i.e. much longer relaxation time) from systems not obeying the first two conditions. Basically, systems with negative temperature are "hotter than infinity" since they will give up energy to any system with positive temperature. The standard example consists of a spin system where more than half the spins point anti-parallel to the applied field: as you increase the energy of the system, fewer and fewer microstates are available. Try googling for an article by Ramsey from the 50's where he talks about thermodynamics with negative temperature.

Hope this helps.
 
Last edited:
wow didnt know. I am going to have to read up about that, but since i have a test tomorrow, I am just trying to understand the more basic cases. Like for the example I gave, the multiplicity function is N choose how many up spins there is, and each up spins means negative energy. So doesn't this concept of negative temperature apply to anything that satisfies those properties (i.e, Multiplicity function g(N,k) N!/(k!(N-k!)) where k is proportional to -U? Or is the case i presented unrealistic because a system with so many down spins will never accept to switch for more down spins, it will instead switch a down spin to gain an upspin so that it can increase the joint multiplicity of the joint system(1+2)?

Edit: actually even if it switches its down spin to gain an upspin, Change in U will be negative and change in entropy will be positive, so its seems like its a general property of any system will the given type of multiplicity function regardless of how it switches its spins. Am i right?
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 53 ·
2
Replies
53
Views
6K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K