- #36

- 23,481

- 5,764

For a galvanic cell, it is possible to carry out a constant external pressure process reversibly by controlling the external voltage applied to the cell so that it nearly matches the cell potential. In such a case, the entropy generated will be zero (##\sigma = 0##), and we will have:

$$w'_{rev}=-\Delta G=-(\Delta H-T\Delta S)$$ and $$q_{rev}=T\Delta S$$ From this it follows that ##-\Delta G## can be interpreted as the reversible galvanic work and ##T\Delta S## can be interpreted as the reversible heat transfer.