Can a threaded tapped joint function as a friction joint?

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9988776655
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I have a tapped hole. A threaded rod goes through the hole. A single nut secures the threaded rod in position. Only one plate is threaded. Note the clearance hole in the top plate. A picture is attached.

A friction joint in a bolt occurs when the clamping force creates a normal force. This normal force is designed to be greater than the friction force between the plates. In this way a bolt does not experience any shear load.

I want to know whether or not a threaded tapped joint can be a friction joint. Specifically, if the clamping force is large enough to prevent slip, then will any part of the threaded rod experience shear?

Thanks.
 
Attachments
  • Cross-section diagram of a threaded rod passing through a clearance hole in a top plate and screwed into a tapped lower plate, with a hex nut on the left end; labels read threaded feature, chip clearance and clearance hole.
    BlindThread11.jpg
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The normal force only depends on the tightness of the bolted joint and the maximum tightness of the bolted joint depends on the yield strength of the bolt. All of this applies whether it is a bolt, a screw or a stud.

Free-body diagrams of a bolted lap joint: two plates pulled apart by forces P, a bolt tightened with a torque arrow, and below it separate diagrams showing clamp normal force N = Tb and friction force Fe = μN on the plate and bolt surfaces.
 
What if there are two threaded fasteners and they are not near each other, each contributing F = uN and each fastener is subjected to a shear force of P/2.
Then does uN > P/2 or does 2uN > P/2 to prevent slipping?
 
9988776655 said:
What if there are two threaded fasteners and they are not near each other, each contributing F = uN and each fastener is subjected to a shear force of P/2.
Then does uN > P/2 or does 2uN > P/2 to prevent slipping?

With the way you chose your words, uN > P/2.
 
What do we do when there is an unequal shear force? eg the shear force on fastener 1 is P and the shear force on fastener 2 is J. Let's assume P > J. Let's assume two fasteners. Then does (uN1 + uN2) > (P/2 + J/2) to prevent slipping? or is it just uN1 > P/2 as before