Can Abel Integral Equations Determine a Curve from Known Area Under It?

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Homework Help Overview

The discussion revolves around the use of Abel integral equations to determine a curve from the known area under it. Participants explore the relationship between area and function representation, particularly in the context of integral equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants question the uniqueness of the curve given a specific area, citing multiple functions that satisfy the same area condition. Others inquire about the applicability of different types of integral equations, such as the first type Volterra equation, in this context.

Discussion Status

The discussion is active, with participants presenting different viewpoints and interpretations of the problem. Some have provided examples of functions that meet the area requirement, while others are probing the implications of the original poster's question and the definitions involved.

Contextual Notes

There are indications of confusion regarding the setup of the problem, particularly concerning the geometric interpretation of the area under the curve and the nature of the rectangle described.

ber70
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If we know area under the curve, are we able to find the curve using Abel integral equations?
 
Last edited:
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Clearly not. Let a region be bounded by the lines x=0, x=1, y=0, and the graph of y=f(x). Let f(x)\geq 0 on \[0,1\], and let the area of the region be 1. There is no unique solution for f(x), as each of the following work:

f_1(x)=1

f_2(x)=2x

f_3(x)=\frac{\pi}{2}\sin(\pi x)
 
Does first type Volterra equation work?
 
Did you comprehend my answer to your first question at all?
 
Question:"Find the curve (or the function) y(x) for which the area under the curve is equal
to \frac{1}{\pi }th of the area formed by the rectangle whose one side is x and the other side is y(x)."

I think \int _a^xy(t)dt=\frac{1}{\pi }y(x).x

give me the curve.
 
Last edited:
ber70 said:
to \frac{1}{\pi }th of the area formed by the rectangle whose one side is x and the other side is y(x)."

You're dealing with a rectangle that has only two sides, one of which is not necessarily a straight line segment? Seriously?
 

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