Can Any Integer Congruent to 3 Modulo 4 Be Expressed as a Sum of Two Squares?

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SUMMARY

The discussion centers on proving that any integer \( a \) congruent to 3 modulo 4 cannot be expressed as the sum of two squares, specifically \( a \neq c^2 + d^2 \) for any integers \( c \) and \( d \). The participant demonstrates that integers of the form \( 4k + 3 \) do not yield valid pairs \( (c, d) \) that satisfy the equation. The analysis includes testing various values and highlights the need to explore the properties of squares modulo 4 to solidify the proof.

PREREQUISITES
  • Understanding of modular arithmetic, specifically modulo 4.
  • Familiarity with integer properties and representations.
  • Basic knowledge of quadratic residues.
  • Experience with proofs in number theory.
NEXT STEPS
  • Study the properties of quadratic residues modulo 4.
  • Explore the proof of Fermat's theorem on sums of two squares.
  • Investigate the implications of integers in different congruence classes.
  • Learn about the structure of integers in the context of modular arithmetic.
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Mathematics students, particularly those studying number theory, educators teaching modular arithmetic, and anyone interested in the properties of integers and quadratic forms.

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Homework Statement


All work is done in the set of integers, Z
a is congruent to 3 modulo 4, Want to prove a=/= c^2 + d^2 for any c or d

Homework Equations


The Attempt at a Solution


My work:
a congruent to 3 modulo 4 => a -3 = 4k
or a = 4k +3
Then want to prove that: 4k+3 =/= c^2 + d^2 *** for any c or dI've tested out some experimental values for 4k+3 and indeed none of them have any c or d that match this equation but I'm not sure how to progress from *** onwards, It is probably a very simple matter but I can't wrap my head around this.
 
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pandaBee said:

Homework Statement


All work is done in the set of integers, Z
a is congruent to 3 modulo 4, Want to prove a=/= c^2 + d^2 for any c or d

Homework Equations





The Attempt at a Solution


My work:
a congruent to 3 modulo 4 => a -3 = 4k
or a = 4k +3
Then want to prove that: 4k+3 =/= c^2 + d^2 *** for any c or d


I've tested out some experimental values for 4k+3 and indeed none of them have any c or d that match this equation but I'm not sure how to progress from *** onwards, It is probably a very simple matter but I can't wrap my head around this.

You can express ANY integer c as 4k, 4k+1, 4k+2 or 4k+3. What are the possible expressions for c^2? In other words, what are the possible values of c^2 mod 4?
 

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