Can Bessel Functions Solve Specific Exponential Trigonometric Integrals?

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    Bessel Integral
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Discussion Overview

The discussion revolves around the integral \(\int^{\phi_{1}}_{\phi_{2}} \exp[j \cos(x)] dx\), specifically exploring whether Bessel functions can be used to solve it. Participants examine the conditions under which the integral yields a Bessel function when evaluated between specific limits.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant, Viet, poses a question about solving the integral and notes that it results in a Bessel function when evaluated from \(\phi_{1} = \pi\) to \(\phi_{2} = 0\).
  • Another participant suggests using the identity \(e^{iz\cos\phi} = \sum_{s=-\infty}^{\infty}i^sJ_s(z)e^{is\phi}\) to approach the integral.
  • A further inquiry is made regarding the reference for the identity, indicating a need for verification or additional resources.
  • One participant references Abramowitz and Stegun as a potential source for the identity mentioned.

Areas of Agreement / Disagreement

Participants appear to agree on the use of the identity involving Bessel functions, but there is no consensus on the availability of references or the completeness of the mathematical framework for solving the integral.

Contextual Notes

The discussion lacks detailed mathematical steps for the integral evaluation and does not clarify the assumptions or conditions under which the identity is applicable.

vvthuy
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Hi,

Do you have any idea to solve this integral?

\int^{\phi_{1}}_{\phi_{2}} exp[j cos(x)] dx

where \phi_{1} and \phi_{2} are an arbitrary angles. If \phi_{1}=\pi and \phi_{2}=0, the answer for this integral is a Bessel function.

Thanks,

Viet.
 
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vvthuy said:
Hi,

Do you have any idea to solve this integral?

[tex]\int^{\phi_{1}}_{\phi_{2}} exp[j cos(x)] dx[/tex]

where \phi_{1} and \phi_{2} are an arbitrary angles. If \phi_{1}=\pi and \phi_{2}=0, the answer for this integral is a Bessel function.

Thanks,

Viet.


Use the identity

[tex]e^{ iz\cos\phi} = \sum_{s=-\infty}^{\infty}i^sJ_s(z)e^{is\phi}[/tex]
 
Mute said:
Use the identity

[tex]e^{ iz\cos\phi} = \sum_{s=-\infty}^{\infty}i^sJ_s(z)e^{is\phi}[/tex]

Thank you very much. Do you have the reference for this equation since I do not find it in my mathematical books?
 

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