I Can Fourier Analysis Represent Any Function Using Sin and Cos?

AI Thread Summary
Fourier analysis utilizes sine and cosine functions due to their orthogonality, allowing any periodic function to be expressed as an infinite sum of these trigonometric functions. The discussion clarifies that while sine and cosine are orthogonal to each other, they are not orthogonal to all functions, which is crucial for the representation of periodic functions. The choice of sine and cosine stems from Fourier's inspiration by the wave equation, making them suitable for harmonic analysis. The conversation also touches on the challenge of finding intervals where the integral of a function equals zero, emphasizing the complexity of the topic. Overall, Fourier analysis remains a powerful tool in scientific applications.
LLT71
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has Fourier used sin(x) and cos(x) in his series because "there must be such interval [a,b] where integral of "some function"*sin(x) on that interval will be zero?" so based on that he concluded that any function can be represented by infinite sum of sin(x) and cos(x) cause they are "orthogonal" to any function.

let me recall my last thread on "orthogonality" as well to see if I got it right or missed the whole point:
https://www.physicsforums.com/threads/orthogonality-of-functions.891717/#post-5611182

extra question: is there possibility that you can find such "a" and "b" where ∫f(x)dx from a to b = zero or at least "try" using some "equation" or so?

thanks!
 
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LLT71 said:
any function can be represented by infinite sum of sin(x) and cos(x) cause they are "orthogonal" to any function
That's not the case and that's not the idea.
You know a little about music ? There are tones and there are overtones (harmonics).
Let's keep it simple and start with periodic functions: functions for which ##f(x+T)=f(x)##. Such ##f## can be written as $$ f(x) = \sum A_n\sin\left ({2\pi nx \over T}\right ) + B_n\cos\left ({2\pi nx \over T}\right )$$precisely because the functions ## sin\left ({2\pi nx \over T}\right ) ## and ## cos\left ({2\pi nx \over T}\right ) ## are orthogonal (wrt each other -- NOT wrt any function). See here what that means.

(If they were orthogonal to any function, all the ##A_n## and ##B_n## would be zero and you wouldn't get anywhere with your summation :smile: )
 
BvU said:
See here what that means.

sorry for late reply (was away from home). your link doesn't work somehow. ok let's reformulate my question: out of all orthogonal functions why did he particularly choosed sin(x) and cos(x)?
 
Because Fourier was inspired by the wave equation.
 
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LLT71 said:
sorry for late reply (was away from home). your link doesn't work somehow. ok let's reformulate my question: out of all orthogonal functions why did he particularly choosed sin(x) and cos(x)?
Harmonics is google search for "harmonic analysis in Fourier series" (google forced a .nl instead of .com in there, perhaps that's the reason it doesn't work).
The other was a paste error and I can't find it back. Crux was that $$\int \sin 2\pi nx \sin 2\pi mx =\delta_{nm}$$ (with some normalization) etc, as here or in point 6 here

:smile:
 
BvU said:
Harmonics is google search for "harmonic analysis in Fourier series" (google forced a .nl instead of .com in there, perhaps that's the reason it doesn't work).
The other was a paste error and I can't find it back. Crux was that $$\int \sin 2\pi nx \sin 2\pi mx =\delta_{nm}$$ (with some normalization) etc, as here or in point 6 here

:smile:
thank you!
 
the problem is difficult!
 
Hello Annarosy, :welcome:

It is and it is not. But Fourier analysis definitely is a very powerful tool in science, so it's worth investing an effort.

micromass said:
Because Fourier was inspired by the wave equation
Check out (our google one that suits your tastes better) e.g. here or http://www.math.harvard.edu/archive/21b_fall_07/handouts/heat_and_wave_equation.pdf
 
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