Can I use this solution? Angular motion

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OrlandoLewis
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Homework Statement


Starting from rest, a wheel has constant α = 3.0 rad/s2. During a certain 4.0 s interval, it turns through 120 rad. How much time did it take to reach that 4.0 s interval?

ω0 = 0
α = 3.0 rad/s2
θf = 120 rad

Homework Equations


Δθ = ω0⋅t + ½αt2

The Attempt at a Solution


120 rad = (1/2)(3.0 rad/s2)(t2)
Solving for t:
t = [2(120 rad) / (3.0 rad/s^2)]½
t = 8.49 s
Subtracting 4.0 s to the said time leads to my final answer, 4.9 s

The book says that the answer should be 8.0 s.
 
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It says "during a certain 4.0s interval " it could be between any time interval.Your equation describes us what is the time when it makes 120 rad we are not looking for that,we are looking for a time interval which object makes 120 rad.
Can you see the difference ?
 
During the given interval, Δθ = 120 rad. But that's not measured from the starting point.

You found the time it takes to go from the starting point to θf = 120 rad, which is a different problem.

Set up two equations.

Edit: Oops, didn't see that Arman777 just said the same thing. :-)
 
Arman777 said:
It says "during a certain 4.0s interval " it could be between any time interval.Your equation describes us what is the time when it makes 120 rad we are not looking for that,we are looking for a time interval which object makes 120 rad.
Can you see the difference ?
It's still pretty vague to me from how you said it. So I'll try to explain as far as I can understand.

At the beginnig it starts to accelerate up to a certain velocity. From that point up to 4 seconds, the said theta is measured until 210 radians.
Is that how I should interpret the problem?
 
OrlandoLewis said:
It's still pretty vague to me from how you said it. So I'll try to explain as far as I can understand.

At the beginnig it starts to accelerate up to a certain velocity. From that point up to 4 seconds, the said theta is measured until 210 radians.
Is that how I should interpret the problem?

It made some rad ##θ_1## between ##t=0## and ##t_1##,
After 4 sec, which let's call is ##t_2## (or ##t_1+4##) it makes ##θ_2## rad (between ##t_2## and ##t=0##)
In between those time intervals (##t_2## and ##t_1##) it makes ##120## rad.
 
Arman777 said:
It made some rad ##θ_1## between ##t=0## and ##t_1##,
After 4 sec, which let's call is ##t_2## (or ##t_1+4##) it makes ##θ_2## rad (between ##t_2## and ##t=0##)
In between those time intervals (##t_2## and ##t_1##) it makes ##120## rad.
Yes, but I feel it could be expressed yet more clearly.
It accelerates at 3 rad s-2 from rest for some time t, turning through some angle in the process. Continuing with the same acceleration for another 4 seconds it turns through a further 120 radians. Find t.