Can I use this solution? Angular motion

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Homework Help Overview

The problem involves angular motion, specifically analyzing the time it takes for a wheel to turn through a certain angle under constant angular acceleration. The original poster presents a scenario where a wheel starts from rest and accelerates at a constant rate, raising questions about the interpretation of the time intervals involved in the motion.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the time intervals and the relationship between the angle turned and the time taken. There is a focus on distinguishing between the total time of motion and the specific intervals during which certain angles are covered.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the time intervals and the angles covered. Some have suggested setting up multiple equations to clarify the relationships involved, while others are seeking clearer expressions of the problem's requirements.

Contextual Notes

There is an emphasis on the ambiguity of the phrasing in the problem statement, particularly concerning the "4.0 s interval" and how it relates to the total angle turned. Participants are questioning the assumptions made in the original poster's approach and the definitions of the time intervals.

OrlandoLewis
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Homework Statement


Starting from rest, a wheel has constant α = 3.0 rad/s2. During a certain 4.0 s interval, it turns through 120 rad. How much time did it take to reach that 4.0 s interval?

ω0 = 0
α = 3.0 rad/s2
θf = 120 rad

Homework Equations


Δθ = ω0⋅t + ½αt2

The Attempt at a Solution


120 rad = (1/2)(3.0 rad/s2)(t2)
Solving for t:
t = [2(120 rad) / (3.0 rad/s^2)]½
t = 8.49 s
Subtracting 4.0 s to the said time leads to my final answer, 4.9 s

The book says that the answer should be 8.0 s.
 
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It says "during a certain 4.0s interval " it could be between any time interval.Your equation describes us what is the time when it makes 120 rad we are not looking for that,we are looking for a time interval which object makes 120 rad.
Can you see the difference ?
 
During the given interval, Δθ = 120 rad. But that's not measured from the starting point.

You found the time it takes to go from the starting point to θf = 120 rad, which is a different problem.

Set up two equations.

Edit: Oops, didn't see that Arman777 just said the same thing. :-)
 
Arman777 said:
It says "during a certain 4.0s interval " it could be between any time interval.Your equation describes us what is the time when it makes 120 rad we are not looking for that,we are looking for a time interval which object makes 120 rad.
Can you see the difference ?
It's still pretty vague to me from how you said it. So I'll try to explain as far as I can understand.

At the beginnig it starts to accelerate up to a certain velocity. From that point up to 4 seconds, the said theta is measured until 210 radians.
Is that how I should interpret the problem?
 
OrlandoLewis said:
It's still pretty vague to me from how you said it. So I'll try to explain as far as I can understand.

At the beginnig it starts to accelerate up to a certain velocity. From that point up to 4 seconds, the said theta is measured until 210 radians.
Is that how I should interpret the problem?

It made some rad ##θ_1## between ##t=0## and ##t_1##,
After 4 sec, which let's call is ##t_2## (or ##t_1+4##) it makes ##θ_2## rad (between ##t_2## and ##t=0##)
In between those time intervals (##t_2## and ##t_1##) it makes ##120## rad.
 
Arman777 said:
It made some rad ##θ_1## between ##t=0## and ##t_1##,
After 4 sec, which let's call is ##t_2## (or ##t_1+4##) it makes ##θ_2## rad (between ##t_2## and ##t=0##)
In between those time intervals (##t_2## and ##t_1##) it makes ##120## rad.
Yes, but I feel it could be expressed yet more clearly.
It accelerates at 3 rad s-2 from rest for some time t, turning through some angle in the process. Continuing with the same acceleration for another 4 seconds it turns through a further 120 radians. Find t.
 

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