Can Ln and Logarithmic Expressions Be Further Simplified?

[skelitor413]

is it possible to simplify this more??

Ln(log₇-log₇6)=

Ln(log₇7)

 

[symbolipoint]

is it possible to simplify this more??

Ln(log₇-log₇6)=

Ln(log₇7)

To start with, some of that does not look correct. You are missing the antilog in one of your "log" expressions. (log₇(ofWhat?)-log₇6)=

 

[symbolipoint]

... to continue, search in your book about adding or subtracting logarithms of the same base. log(A) + log(B) = ? and log(A) - log(B) = ?

 

[HallsofIvy]

is it possible to simplify this more??

Ln(log₇-log₇6)=

Ln(log₇7)

Persumably you mean ln(log₇ x- log₇ 6) for some number x that you forgot. Certainly log₇ x- log₇ 6= log₇(x/6). If that is, as you appear to be saying, log₇ 7, then x must have been equal to 7(6)= 42.
Yes, ln(log₇(42)- log₇(6))= ln(log₇ 7)

Further, by the very definition of log, log₇= 1 so what you have reduces to just ln(1)= 0. It that simple enough?