Can Machine Gun Bullets Propel a Vehicle to Required Speeds?

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SUMMARY

The discussion centers on calculating the number of bullets required to propel a 100 kg test vehicle to a speed of 19.0 m/s using a machine gun. The vehicle, equipped with a sail made of ultrahard steel, is tested on frictionless rails. The analysis reveals that each bullet, weighing 20.0 g and traveling at 400 m/s, exerts an impulse of -10 Ns upon rebounding at 100 m/s. To achieve the desired speed within 30 seconds, the calculation concludes that 6.33 bullets must be fired per second.

PREREQUISITES
  • Understanding of momentum and impulse concepts
  • Familiarity with basic physics equations, specifically p=mv and J=change in momentum
  • Knowledge of unit conversions, particularly between grams and kilograms
  • Ability to perform calculations involving rates and time
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  • Study the principles of impulse and momentum in physics
  • Learn about the mechanics of projectile motion and its applications
  • Explore advanced calculations involving frictionless systems
  • Investigate the implications of using kinetic energy in propulsion systems
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Physics students, engineers involved in propulsion systems, and military strategists interested in innovative vehicle propulsion methods will benefit from this discussion.

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Homework Statement


The Army of the Nation of Whynot has a plan to propel small vehicles across the battlefield by shooting them, from behind, with a machine gun. They've hired you as a consultant to help with an upcoming test. A 100 kg test vehicle will roll along frictionless rails. The vehicle has a tall "sail" made of ultrahard steel. Previous tests have shown that a 20.0g bullet traveling at 400 m/s rebounds from the sail at 100 m/s. The design objective is for the cart to reach a speed of 19.0 m/s in 30.0 s . You need to tell them how many bullets to fire per second from the machine gun. Note that your answer should be a rate, which can be fractional, rather than a quantity, which must be an integer.


Homework Equations


p=mv J=change in momentum


The Attempt at a Solution


I found the impulse exerted on a bullet.
J=(.02kg)(-100m/s)-(.02kg)(400m/s)
J= -10 Ns

Then I set up an equation to find what impulse needs to be exerted on the cart to speed up to 19 m/s:

0kgm/s + J = (100kg)(19 m/s)
J=1900 Ns

Then I assumed the impulse exerted on a bullet is the same as the impulse exerted on the sail by a single bullet :

1900Ns* (1 bullet/10Ns) =190 bullets
I then divided that by 30 sec. & came up with 6.33 bullets/sec.

Is this correct?
 
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Your math is correct and I ran through your procedure and it looks sound.
 
… Because … Because … Because … !

The Nation of Because regards your militaristic experiments as a threat to our beliefs! :frown:

The ancient Nation of Because will always defeat the Nation of Whynot!

:mad: Go to your room! :mad:
 

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