Can Oscillating Charges Emit a Hydrogen-Like Spectrum Through Prism Dispersion?

[Hydr0matic]

What I'm asking is if an EM wave, emitted by a charge oscillating vertically and horisontally, could produce multiple discrete lines when passed through a prism.

A sinusoidal oscillation will produce a "pure" wave of one frequency, so that only one spectral line will be produced. Any other type of oscillation will produce harmonics so that a discrete spectrum will be produced.

That is an exact answer, by the way.

so IN THEORY, there should be an oscillation pattern that yields the hydrogen spectrum ?

 

[maverick280857]

HI

This is an interesting issue...could you please rephrase your question though before I can give you my answer...

I mean more generally, can you describe what you mean when you say

so IN THEORY, there should be an oscillation pattern that yields the hydrogen spectrum ?

Going back to a very basic idea...if you could set up a wave equation the spherical harmonics of which when analyzed with the radial wavefunction should be able to explain fine structure in the hydrogen spectrum (this seems to deviate from your original question but still, the hydrogen spectrum analysis is characterized by fine structure and not by the classical approach which fails to explain orbital degeneracy and fails to account for the experimentally observed spectrum). When you say, "yields the hydrogen spectrum", you probably mean this mathematically:

Can we get a function to reprsent this oscillation pattern?

Please correct me if I am wrong...

Cheers
Vivek

 

[Hydr0matic]

When you say, "yields the hydrogen spectrum", you probably mean this mathematically:

Can we get a function to reprsent this oscillation pattern?

It could be represented by a Fourier sum, right ? ..

My intent with the thread was to

first, conclude that the hydrogen spectrum could be produced by a classical electromagnetic wave (i.e. discrete spectrum does not contradict the wave theory of light (might not be obvious to everyone)).

second, discuss how such waves could be emitted and what sources could produce 'em.

third, explain my idea on this matter and discuss it.

Going back to a very basic idea...if you could set up a wave equation the spherical harmonics of which when analyzed with the radial wavefunction should be able to explain fine structure in the hydrogen spectrum (this seems to deviate from your original question but still, the hydrogen spectrum analysis is characterized by fine structure and not by the classical approach which fails to explain orbital degeneracy and fails to account for the experimentally observed spectrum).

I believe my idea is much more basic than this. Think about this:
A charge is oscillating sinusodial along the y-axis. Sinusodial waves are emitted perpendicular to the oscillation. What do the waves emitted at all other angles look like ? Are they sinusodial ? If not, what do they look like and what kind of spectrum would they produce ?

 

[maverick280857]

Hello Hydr0matic

Thanks for rephrasing your original question...interesting idea.

Usually, if a the graph is viewed from a different angle, you see its projection and obviously not the original thing as it was being produced.

Cheers
Vivek

 

[kuengb]

I believe my idea is much more basic than this. Think about this:
A charge is oscillating sinusodial along the y-axis. Sinusodial waves are emitted perpendicular to the oscillation. What do the waves emitted at all other angles look like ? Are they sinusodial ? If not, what do they look like and what kind of spectrum would they produce ?

That's a Hertz dipole. If you're far enough away (distance>>oscillation amplitude), the radiation is harmonic in all directions. What changes is intensity (max. at the "equator", min. at the "poles").

 

[Hydr0matic]

(max. at the "equator", min. at the "poles")

This is basically my point, yes - the angle of emission. A simple harmonic oscillator will emit a sinusodial wave perpendicular to it's direction of oscillation, and the amplitude of the wave is dependant on the angle between the emitted wave and the oscillator.

BUT, what about the waves not emitted perpendicular ? Are they sinusodial ?

 

[Hydr0matic]

BUT, what about the waves not emitted perpendicular ? Are they sinusodial ?

They're obviously not sinusodial. Because, at an angle not perpendicular to the direction of oscillation, the relative oscillation is both vertical and horisontal.

So what kind of spectrum will these non-sinusodial waves produce ?

What do the waves emitted at different angles have in common ?


Do anyone else think this sounds interesting ? or should I just shut up ?

 

[jtbell]

For the radiation emitted by a sinusoidally oscillating electric dipole, see for example Griffiths, Introduction to Electrodynamics, chapter 9. The formula is simplest in spherical coordinates. of course, so let the dipole oscillate along the z-axis with angular frequency \omega, with maximum dipole moment p_0:

\bold E = -\frac {\mu_0 p_0 \omega^2}{4 \pi} \left(\frac {\sin \theta}{r}\right) \cos [\omega (t - r/c)] \hat \theta

The direction of the electric field is only in the polar direction, which is the direction of longitude lines on a globe. There is no radial or azimuthal component. The field is perpendicular to the direction of propagation (the radial direction) at all points.

Similarly, the magnetic field is only in the azimuthal direction, which is the direction of latitude lines on a globe. There is no radial or polar component. This field is also perpendicular to the direction of propagation at all points.

And the oscillation is always sinusoidal in time.

 

[Hydr0matic]

Thanx jtbell.. I realize I haven't been that clear in my posts. I'm specifically talking about the radiation emitted by an oscillating electric monopole.

The direction of the electric field is only in the polar direction, which is the direction of longitude lines on a globe. There is no radial or azimuthal component. The field is perpendicular to the direction of propagation (the radial direction) at all points.

Similarly, the magnetic field is only in the azimuthal direction, which is the direction of latitude lines on a globe. There is no radial or polar component. This field is also perpendicular to the direction of propagation at all points.

Again I'm unclear. With "direction of oscillation" I meant the axle along which the monopole is oscillating.

And the oscillation is always sinusoidal in time.

True. Which is why all waves emitted by the monopole have the same wavelength. BUT, if we were to represent a wave emitted by the monopole with a line - again, one that's not emitted perpendicular - the line would not be sinusodial. I.e. all waves, except for the ones emitted perpendicular, will be "unpure", as Tyger put it.
They will not produce the single "pure" discrete line in a spectrum that the perfectly sinusodial would.
So the question is, what would they produce ?

 

[Tide]

If the charged particle is oscillating "horizontally and vertically" and both are at the same frequencey then it will generate (monochromatic) elliptically polarized radiation at the same frequency and possibly harmonics of the fundamental. This will not resemble the hydrogen spectrum. At extreme amplitudes it might resemble synchrotron radiation.

 

[reilly]

I would suggest a review of the history of atomic spectra might be useful. What you will find is: classical physics could not explain nor generate the type of motion that would produce discrete spectra. Further, the mechanics of a radiating charge require that the charge lose energy. As a result, Rutherford's atom could not exist, contrary to experiment.

This vexing problem drove crazy many of the finest minds at the turn of the 20th century. Then Bohr, with a stroke of extraordinary genius, proposed a simple model that opened the door to the quantum theory of atoms -- which quite nicely explains discrete spectra with all of its physical subtleties.

Regards,
Reilly Atkinson

 

[Hydr0matic]

If the charged particle is oscillating "horizontally and vertically" and both are at the same frequencey then it will generate (monochromatic) elliptically polarized radiation at the same frequency

I've expressed myself vaguely again. My apologies. A monopole oscillating along a straight axle will not generate this elliptically polarized radiation, I believe. Only a circular motion would, correct ? By "horizontally and vertically" I meant the relative movement of the oscillator, viewed from an angle not perpendicular to it's direction of oscillation. (horizontally is not the right word since the movement relative to the non-perpendicular wave is towards/away from - i.e. z-axle).

.. and possibly harmonics of the fundamental.

An oscillating monopole moving along a straight axle - would it or would it not produce harmonics of the fundamental at any angle except perpendicular and along the axle (0°)?

Follow up question - Am I right in guessing that the non-perpendicular waves would basically consist of one half a period where the wave is blueshifted, and one half a period where the wave is redshifted ? (i.e. during one half of the period the monopole is moving towards the emitted wave, and the other half it's moving away from it).

This will not resemble the hydrogen spectrum.

Please, I know I don't exactly come off as a physics professor, but don't insult my intelligence. I'm not finished yet. There's a reason why I'm taking this step by step. Just blurting it out would result in gibberish worthy of a crackpot, since I'm obviously not expressing myself clear enough half of the time. Let me get to the end before you chop my legs off

I would suggest a review of the history of atomic spectra might be useful. What you will find is: classical physics could not explain nor generate the type of motion that would produce discrete spectra. Further, the mechanics of a radiating charge require that the charge lose energy. As a result, Rutherford's atom could not exist, contrary to experiment.

Thanx reilly, but I know my history quite well. What you're saying about classical physics is simply not true - discrete spectra does not contradict the wave theory of light..
Concerning Rutherford's atom - I agree, it could not exist. But I'm not talking about an electron circulating a proton. I'm simply discussing an oscillating monopole. If what I believe is correct, the most fundamental discrete spectrum is simply a result of the simplest oscillating motion.

 

[Tide]

HydrO,

I was only trying to help out. I look forward to your "real" question. :-)

 

[Hydr0matic]

I was only trying to help out. I look forward to your "real" question. :-)

I know, I'm sorry. I appreciate your help.

Once we establish what kind of harmonics the monopole radiates, there's only one thing left to explain..

You suggested that the non-perpendicular waves would produce more than a one line spectrum, correct ? .. Do you have an idea how the spectrum might look, perhaps ?

 

[reilly]

Hydr0matic -- You are correct that there's nothing in the wave theory of light that precludes discrete spectra -- think for a moment about the actual quantum theory of radiation -- based on Maxwell's equations, which in first order QM perturbation theory is virtually identical to classical E&M.

The problem is with the motion of the charges, which should be evident from Bohr's and subsequent theories. I assume that by monopole you mean a single charge. If so, then I refer you to any graduate level E&M text, Jackson, Panofsky and Phillips, Landau and Lef****z, or whatever. There you will find first that if a charge oscillates at frequency f, the emitted radiation will have frequency f and only f. Second, an oscillating charge will have a full set of multipoles -- dipole, quadrapole, and so forth -- which determine the angular distribution of radiation. To get discrete spectral lines with f1, f2, and so forth requires charges oscillating at f1, f2 and so on. And there's the rub: what kind of motion will produce discrete spectra? Quantum "motion", which, by fiat, allows discontinuous "motion".

Your real mission, should you chose to accept it, is to figure out how a classical motion can generate discrete spectra, and how to make the charge complex absorb only certain frequencies. Your problem is with the source, not the radiated fields. And, you will also need to explain Rutherford's expt. with your theory. Good luck.

Regards,
Reilly Atkinson

PS If your monopole is not a single charge, what is it?

 

[Hydr0matic]

First of all, thank you thank you thank you!.. for getting this discussion somewhere.. I really appreciate it.

The problem is with the motion of the charges, which should be evident from Bohr's and subsequent theories. I assume that by monopole you mean a single charge. If so, then I refer you to any graduate level E&M text, Jackson, Panofsky and Phillips, Landau and Lef****z, or whatever. There you will find first that if a charge oscillates at frequency f, the emitted radiation will have frequency f and only f.

This is exactly where the misconception lies. Yes! - all radiation will have frequency f, and yes, all waves will have the same wavelength from top to top. BUT, any wave not emitted perpedicular will not be sinusodial. I cannot stress the importance of this fact more. Lightwaves are not limited to sinusodial oscillation! As a result, a wave that clearly appears to have a certain frequency when viewed as a whole, might actually consist mainly of other frequencies.
An analogy is temperature - we say an object has a certain temperature, but in fact, that temperature might not exist anywhere within that object, i.e. different parts of the object might have different temperatures.

Have a look at these waveforms:
http://hydr0matic.insector.se/fysik/oscillationpatterns.jpg

The first one is supposed to be sinusodial but it's not quite "pointy" enough. Never mind.
Take a look at waveforms 2 & 3 - they both have the same frequency and wavelength as the first one. Yet, clearly they are not the same waves. The second one has a mid-phase acceleration to it, and the third one has additional z-oscillation.
The third type is the one I've been discussing in this thread, emitted by oscillating monopoles.
This wave illustrates my point about the appearance of a certain frequency, but with other "internal" frequencies. As you can see the troughs of the wave have been shifted to the left creating what appears to be (roughly) two separate parts - one blueshifted and one redshifted.

To avoid being unclear about too much I'll stop here for now..

Am I completely clueless in the above explanation, or am I on to something ?

 

[reilly]

Since you raised the issue, yes, with all due respect, you are clueless about radiation. If you will take the time to study just a bit you'll certainly be forced to change your tune about the relation between particle oscillatory frequencies and radiation frequencies. You are dealing with material that's been examined with extraordinary vigilence for well over a century, and has stood the test of time. The onus is on you to give a clear and compelling argument why most of us are wrong. a good place to start is to explain the wave forms you have drawn -- what are they, how were they derived.

Regards,
Reilly Atkinson

 

[T.Roc]

Hydr0matic,

while you are correct in saying that a perceived frequency may contain other frequencies, you have not demonstrated this with the 3 waveforms on your link.

you have left out the direction of the wave, which when viewed at right angles, can be seen in its' true form - symmetry. the 3 forms you showed are the same wave viewed at different angles, and the perception of the same wave changes. a donut viewed at 90' is a line, at 45' an oval, and at 0' (or 180') is a circle; but these are all just different perceptions of the same donut. the Fourier form is still symmetrical.

TRoc

 

[Hydr0matic]

Since you raised the issue, yes, with all due respect, you are clueless about radiation.

Maybe I am, I'll find out soon enough..

The onus is on you to give a clear and compelling argument why most of us are wrong.

I didn't realize I was saying something that was so outrageous ? Take a look at the quotes I started this thread with. Tyger said any wave that isn't sinusodial will produce harmonics, he even claims it to be an exact answer. If he's wrong, why haven't anyone pointed that out ?
The fact of the matter is, I'm not saying anything at all that isn't in line with classical EM ..(the physics, not the beliefs).

a good place to start is to explain the wave forms you have drawn -- what are they, how were they derived.

They weren't, I drew 'em just to illustrate my point about waves that have the same apparent frequency and wavelength still being very different from each other.

I realize they are just lines on a surface, but... Try to look beyond the poor representation and focus on what I'm trying to say.

The waves are all viewed from the same angle, the only thing that changes is the motion of the charge on the left. They are three separate examples of oscillatory motion producing different waves with the same apparent wavelength.

Let's say you are observing an oscillating monopole right in front of you and you can see it's oscillatory motion (ignore the scale differences). Just standing there watching the oscillator swing up and down along the y-axle, you notice the sinusodial wave hitting you has the same frequency as the oscillating motion of the monopole.
Now, the monopole starts moving away from you along the z-axle while it's oscillating. Instantly you notice a redshift in the waves hitting you. The monopole then slows down and starts moving towards you again - a blueshift occurs.
The monopole repeats this motion back and forth along the z-axle and you realize the z-motion obviously has an effect on the radiated waves. An effect, more known as the Doppler effect.
Now, what would happen if the z-motion of the monopole back and forth would get smaller and smaller, turning into what could be considered as an oscillatory motion along the z-axle ? Would the Doppler effect suddenly disappear ? .. Would the motion along the z-axle suddenly stop having an effect on the waves you see ? ..

If you only answer one question in your next reply, let it be this:
Are all waves radiated by an oscillating charge sinusodial ?

Then read Tyger's quote again ...

 

[Hydr0matic]

you have left out the direction of the wave, which when viewed at right angles, can be seen in its' true form - symmetry. the 3 forms you showed are the same wave viewed at different angles, and the perception of the same wave changes. a donut viewed at 90' is a line, at 45' an oval, and at 0' (or 180') is a circle; but these are all just different perceptions of the same donut. the Fourier form is still symmetrical.

This was not my intent with the illustration. The waveforms are completely independent of each other, and they are all viewed from the same angle - perpendicular to the direction of the waves. The only thing that changes is the oscillatory motion of the charge on the left.

while you are correct in saying that a perceived frequency may contain other frequencies

Thanx T.Roc... Would you also confirm my suspicion that the non-perpendicular waves radiated by an oscillating monopole, contains such other frequencies ? ... (other than the perceived frequency f of the monopole).

 

[T.Roc]

Hydr0matic,

i realize that it was not your intention to illustrate the same wave from different angles, but i was pointing out that that is what you have done.

i think we need to get to the heart of the matter. all EM waves oscillate on 2 axis that are perpendicular to each other. a single oscillating charge will generate an electric wave that will automatically generate a magnetic wave that is perpendicular and symmetrical to the first. in this way, it propels itself at c.

if you want to create a theoretical wave form in the shapes you have given, you have to realize 2 things. 1- they can not be produced by simple harmonic motion, and 2- they can not be viewed at a perpendicular angle because they will not move in a single (straight) direction. (yes, in the initial frame you could, but then, because the direction is "curved", the following frames would not be perpendicular, causing the "perception" of non-symmetry)

if you want to find "hidden" frequencies within a complex wave form, go back to Fourier analysis. they are symmetrical, move in a single and straight direction, and are perpendicular to the initial electric field (or energy release).

perhaps now is a good time to share your thoughts on how this relates to the H spectrum?

TRoc

 

[Hydr0matic]

if you want to create a theoretical wave form in the shapes you have given, you have to realize 2 things. 1- they can not be produced by simple harmonic motion, and 2- they can not be viewed at a perpendicular angle because they will not move in a single (straight) direction. (yes, in the initial frame you could, but then, because the direction is "curved", the following frames would not be perpendicular, causing the "perception" of non-symmetry)

I believe you are reading too much into my illustrations. I was simply trying to illustrate that two waves with the same wavelength aren't necessary exactly the same.

if you want to find "hidden" frequencies within a complex wave form, go back to Fourier analysis. they are symmetrical, move in a single and straight direction, and are perpendicular to the initial electric field (or energy release)

complex? hidden? .. I simply want an analysis of the waves emitted by an oscillating monopole. If it is the case that all emitted waves are sinusodial, then there's nothing more to it. I was wrong, end of story.

If you only answer one question in your next reply, let it be this:
Are all waves radiated by an oscillating charge sinusodial ?

You seem to know a lot about this thing, so how would you answer this question ? .. (if a short answer is possible, I would prefer it)

perhaps now is a good time to share your thoughts on how this relates to the H spectrum?

It wouldn't make sense if I told you now. Not until we've clearly established if monopoles can create harmonics, i.e. if all waves emitted by the monopole are sinusodial.

 

[Caroline Thompson]

Your real mission, should you chose to accept it, is to figure out how a classical motion can generate discrete spectra, and how to make the charge complex absorb only certain frequencies. Your problem is with the source, not the radiated fields. And, you will also need to explain Rutherford's expt. with your theory. Good luck.

When you hit a bell, it produces a whole host of different frequencies. I imagine each of these is "discrete". It's surely not impossible for an atom (or molecule) to do the same. I can't visualise how a bell manages to produce all those notes, so it is hardly surprising that I can't visualise the atom. The answer must be that both bell and atom are complex structures with many degrees of freedom?

When it comes to absorption, the atom is going to couple best with one of its natural frequencies. It will preferentially "absorb" it.

Which of Rutherford's experiments had you in mind?

Caroline
http://freespace.virgin.net/ch.thompson1/

 

[Hydr0matic]

Perhaps this animation can be of some help:
http://www.upscale.utoronto.ca/GeneralInterest/Harrison/Flash/EM/LightWave/electricfieldwaves2.html

The author: http://www.cs.sbcc.cc.ca.us/~physics/di-home.html

Is this animation a fairly accurate representation of the electrical fields around an oscillating charge ?

In this animation, do you see:
1. that all waves have the same wavelength from crust to crust ?
2. that waves not emitted perpendicular are not sinusodial ?

 

[reilly]

Caroline -- You are quite correct about the bell, so I have to admit that I was less than precise. Yes, there are classical systems governed by eigenvalue equations (strings, vibrating membranes, and so on), and so have discrete vibration patterns. But, how do you propose to "construct" such a model. for an atom, that will send and receive discrete radiation frequencies? (It takes electrical engineers a bit of doing to build circuits that will discriminate various discrete frequencies.)

I mean by "Rutheford's Expt." the one with the alpha particles, that gave birth to the spectacularly successful modern atomic physics. So, it seems to me that any atomic model, however constructed, must have virtually all, but not all, its matter concentrated in what we call a nucleus.

Hydr0matic - For a single frequency wave, the spatial part of the wave need not be sinusoidal, only the time part need be so. For example, with digital electronics, it's easy to construct a single frequency square wave, one that you can see on a scope. As long as the spatial pattern over a distance of the wavelength is invariant, the wave can be a monochromatic wave of any frequency.

Regards,
Reilly Atkinson

 

[T.Roc]

hydro,

the link for the animation is exactly what i was talking about. the waves are sinusoidal, it is only the perspective of each, according to their angle viewed, that changes. if you could rotate the image one "degree" clockwise, you would see that they are the same form when they are perpendicular to the direction viewed. notice the parallel lines (0' and 180') don't look like waves at all, just as the donut wouldn't look round at those angles.

caroline: the way that only disreet waves are produced is that "only the strong survive"; reinforced waves carry on, while the dis-harmonic ones cancel out. if you turned your bell upside down and marked lines around it n inches apart, each diameter would have a frequency that was a harmonic of the natural frequency (the largest diameter/wavelength). the same for the atom. the energy and wavelength have inverse relations.

TRoc

 

[Hydr0matic]

Thanx guys, but none of you seem to have really answered my question. Never mind that... what T.Roc just posted is incredible from my stand point. He basically took the words right of my mouth:

the way that only disreet waves are produced is that "only the strong survive"; reinforced waves carry on, while the dis-harmonic ones cancel out. if you turned your bell upside down and marked lines around it n inches apart, each diameter would have a frequency that was a harmonic of the natural frequency (the largest diameter/wavelength). the same for the atom. the energy and wavelength have inverse relations.

Excuse me if I'm too entusiastic about this but, THIS IS EXACTLY WHERE I WAS GOING! (with this thread) ...

If what I believe about the radiation from an oscillating charge is correct, then all waves not emitted perpendicular will be shifted due to the oscillator's relative angle. This means that all non-perpendicular waves will contain mainly two frequencies that are harmonics of the natural one - one redshifted and one blueshifted. The amount of shifting will be a function of the angle. This means that, if we combine all the radiation emitted by the oscillator in a spectrum, it will basically consist of a continuous spectra where the natural frequency is centered between the more or less blue- and redshifted ones.
BUT, not all of these frequencies will be visible, since only a few of them are reinforced, i.e. the dis-harmonic ones will cancel out.
Only the blueshifted frequencies that are evenly dividable with the natural frequency are reinforced! .. The final visible spectrum will thereby be one that resembles a hydrogen-series.

 

[Hydr0matic]

This thread is a continuing of a previous one: https://www.physicsforums.com/showthread.php?t=4676

I didn't get any response from that one so.. I tried a different approach. Hope it worked.

 

[reilly]

Hydr0matic: re your other post. You can calculate the radation pattern generated by your various waveforms, both spatially and temporally, by the century-tested Maxwell Eq.s. You'll get a wave equation(s) with your oscillation patterns as the source. So you will be able to answer your questions quite thoroughly with a few integrations.

Regards,
Reilly Atkinson

 

[Hydr0matic]

reilly, please.. give me a break, it's a yes or no question. Are all waves emitted by an oscillating charge sinusodial ?

Since you've obviously done the calculations, why can't you just tell me - yes or no ?

 

[T.Roc]

hydro,

are you aware that each spectral line (color) is created by a drop in "orbit" from an electron previously energised by a harmonic frequency (photon)?

i don't think the doppler effect (red/blue shift) is related to the spectrum. doppler is moving toward, then away from, the observer. in emission / absorbtion, the direction is from one to the other.

TRoc

 

[Hydr0matic]

are you aware that each spectral line (color) is created by a drop in "orbit" from an electron previously energised by a harmonic frequency (photon)?

Omg, you must really think I'm an idiot. Yes, I'm very familiar with the atomic model... Thomson's, Bohr's, Schrödinger's. I've read a lot of QM, although mostly on a conceptual level. But I've just taken a full semester of university math last spring, so any math you'd like to use in explaning would not go over my head.

i don't think the doppler effect (red/blue shift) is related to the spectrum. doppler is moving toward, then away from, the observer. in emission / absorbtion, the direction is from one to the other.

I know what I'm trying to expain isn't what is usually considered doppler. Doppler is considered a macro effect, and now I'm applying it on oscillators. I know it seems crazy, but I don't know how else to explain it.
Think about it, when exactly does doppler apply ? Does it matter on what distances the relative motion takes place ? Does it matter if the relative motion is over distances of 1 lightyear or a few nano meters ? .. As I interpret it, ANY motion (of the source) towards or away from the observer should be considered doppler. Even if this relative motion is a few nanometers back and forth during the time span of an oscillator's period. It shouldn't matter. The oscillator is moving at such speeds there's bound to be major wavelength shifts as a result of any z-movement relative the observer.

 

[reilly]

Hydr0matic -- I'm an ex-professor of physics, so I answer questions with questions. You'll find your answers if you will spend an hour or two reading about radiation in a physics book or two. I will, once again, suggest a clue: waves can be sinusoidal in time, and, independently sinusoidal or not in space as well.
Regards,
Reilly Atkinson

 

[Hydr0matic]

Hydr0matic -- I'm an ex-professor of physics, so I answer questions with questions. You'll find your answers if you will spend an hour or two reading about radiation in a physics book or two.

I doubt it. Any answers I'll find there should also be available on the internet. However, I have spent countless hours and long nights searching for it, unsuccessfully.
All I can find is descriptions of the radiation emitted perpendicular to the oscillator.

I will, once again, suggest a clue: waves can be sinusoidal in time, and, independently sinusoidal or not in space as well.

When you say "or not", are you referring to "independently" och "sinusoidal" ?
I already know that EM waves can be non-sinusoidal. The question is whether or not the non-perpendicular waves emitted by an oscillating charge are sinusoidal. I know they're not, I just want it confirmed so we can move on with this discussion.

 

[Hydr0matic]

the link for the animation is exactly what i was talking about. the waves are sinusoidal, it is only the perspective of each, according to their angle viewed, that changes. if you could rotate the image one "degree" clockwise, you would see that they are the same form when they are perpendicular to the direction viewed. notice the parallel lines (0' and 180') don't look like waves at all, just as the donut wouldn't look round at those angles.

T.Roc, I understand what you're talking about. And the animation is first and formost meant to be viewed like you describe - all waves are sinusoidal ones emitted perpendicular to the oscillator, just viewed from different angles. However, this animation could also serve a different purpose as a cross-section of the radiation emitted at all angles. In this view, the lines 0° and 180° illustrate the fact that no radiation is emitted along the oscillating axle.

[ Since the cross-section view isn't the original purpose of this animation, the speed of light is too slow, almost making the crusts "tip over" the troughs. ]

 

[T.Roc]

hyrdo,

ok - photons(n energy) are created when an electron fall back to its' previous orbit after being bumped to a higher orbit by a photon of the same energy (n) - we are on the same page, and i didn't think you are an idiot.

the other lines in the spectrum (photons) are EACH created by subsequent changes in the possible orbits for the nucleus. every line you see is created by a different photon (frequency).

your idea seems to be that one oscillation is making all these photons? not so. if you want to look at this with wave forms, that is fine. the straight line between the emitter and receiver (90') is all that is required because for every angle above 90', there is a symmetrical angle below 90', and they cancel each other out.

even if this were not the case, the harmonics created by such a small range of frequency change is not enough to produce the wide range seen in the hydrogen spectrum (or others). ie. - you might get a "red" to "red-orange" change, but not orange to violet, and definitely not IR through visible and into UV.

TRoc

 

[Hydr0matic]

your idea seems to be that one oscillation is making all these photons?

Well that's the beauty of it .. By explaining discrete spectra as a result of atomic motion, you don't actually need to infer any energy levels at all. ... Of all the crazy statements you've ever heard, this takes the cake huh ? ... "We don't need atomic energy levels" .. wow, I even amaze my self.

Ironically, this isn't that far from our current model, is it? We started out with planetary orbits, then energy levels were introduced with fixed orbits. Now, there's a wavefunction for each electron describing the probability of finding it in a certain position.
Is it just me or is this another way of saying "- the electrons are somewhere within the atom" .. Were it not for the fact that each electron is associated with a certain energy level...

not so. if you want to look at this with wave forms, that is fine. the straight line between the emitter and receiver (90') is all that is required because for every angle above 90', there is a symmetrical angle below 90', and they cancel each other out.

Yes, I realize that. Of course, you need more than one oscillating atom to get a visible spectrum. Like, perhaps, a cloud of atoms oscillating in random directions.

even if this were not the case, the harmonics created by such a small range of frequency change

What makes you say it's small? The atoms are oscillating at very high speeds. And the amount of shifting is obviously very depent on the oscillator's speed.