Can someone help me find which object is in static equilibrium?

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Homework Help Overview

The discussion revolves around identifying which object is in static equilibrium based on the forces acting on it. Participants are analyzing different options and the balance of forces involved.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are discussing the balance of forces in various options, questioning whether two forces can balance one, and exploring the conditions for static equilibrium.

Discussion Status

The conversation is ongoing, with participants providing arguments and clarifications regarding the forces involved. Some have suggested that the phrasing of arguments could be improved for clarity, and there is an exploration of multiple options (C and D) based on the reasoning presented.

Contextual Notes

Participants are considering the visual representation of the forces and their lateral displacements, which may affect their interpretations of the problem. There is also mention of specific conditions that must be met for static equilibrium.

Pawn
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Homework Statement
The magnitudes of the forces is not given
Relevant Equations
F net = F1+F2+F3... =0
20220228_112124.jpg
 
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Welcome!
Please, explain which is your choice and why?
 
Lnewqban said:
Welcome!
Please, explain which is your choice and why?
I chose B because the two forces in the right side are acting in the sides of the object while the one which is facing to the left is in the middle so i thought they will balance.
(the forces have the same magnitude in option B)
 
Pawn said:
I chose B because the two forces in the right side are acting in the sides of the object while the one which is facing to the left is in the middle so i thought they will balance.
(the forces have the same magnitude in option B)
Are two not more forceful than one?
 
PeroK said:
Are two not more forceful than one?
So the correct option is D ?
 
Pawn said:
So the correct option is D ?
What is your argument? Presenting that will give you better feedback than a simple yes/no.
 
Orodruin said:
What is your argument? Presenting that will give you better feedback than a simple yes/no.
Because the force that's acting on the left is twice that of the force that is acting in the right so the net force will be zero.
 
Pawn said:
Because the force that's acting on the left is twice that of the force that is acting in the right so the net force will be zero.
There's something not quite right about the way you've phrased that. What about "the single force on the left is equal in magnitude to ... forces on the right". Can you fill in the blanks?
 
PeroK said:
There's something not quite right about the way you've phrased that. What about "the single force on the left is equal in magnitude to ... forces on the right". Can you fill in the blanks?
The single force on the left is equal in magnitude to the sum of magnitudes of the forces on the right .
 
  • #10
Pawn said:
The single force on the left is equal in magnitude to the sum of magnitudes of the forces on the right .
That sounds better. "Sum" is the key word here, in my opinion.
 
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  • #11
Two conditions have to be fulfilled in order that a rigid body is in static equilibrium:
  • The sum of the external forces on the rigid object must equal zero
  • The sum of the external torques on the rigid object must equal zero
 
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  • #12
Pawn said:
The single force on the left is equal in magnitude to the sum of magnitudes of the forces on the right .
That leaves us both C and D. So which is it ?
 
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  • #13
BvU said:
That leaves us both C and D. So which is it ?
If you follow the thread back, that was in reference to option D.

It could have been better drawn, though. The two forces on the right appear to be equal in magnitude but are visibly not the same lateral displacement from the force on the left.
 

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