Can someone me find the magnitude of acceleration using forces?

Click For Summary
SUMMARY

The discussion focuses on calculating the magnitude of acceleration for an 8 kg mass subjected to two forces: 145 Newtons at an unknown angle and 16 Newtons at 24.5 degrees below the negative x-axis. The correct approach involves resolving forces vertically to determine the angle at which the mass begins to leave the surface, leading to the equation 145sin(θ) = 16sin(24.5) + 8(9.8). This results in an angle θ of 35.9 degrees. Subsequently, horizontal forces can be resolved to find the acceleration accurately.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of vector resolution of forces
  • Familiarity with trigonometric functions (sine and cosine)
  • Basic principles of dynamics and motion on frictionless surfaces
NEXT STEPS
  • Study vector resolution techniques in physics
  • Learn how to apply Newton's laws in two-dimensional motion
  • Explore the concept of static friction and conditions for motion
  • Practice problems involving forces at angles and their resultant effects
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators looking for examples of force resolution and acceleration calculations.

shaunamariexx
Messages
2
Reaction score
0

Homework Statement


A mass of 8 kg lies on a frictionless, horizontal floor. A force of 145 Newtons is applied to the mass at an angle above the positive x-axis and a force of 16 Newtons is applied to the mass at an angle of 24.5 degrees below the negative x direction. If the angle for 145 Newtons is increased until the object just starts to leave the surface, what is the magnitude of the acceleration on the mass in m/s2 at this point?

The Attempt at a Solution


F1=145 N with unknown angle
F2=16 N with angle of 24.5 degrees
F=ma
145N=8kg(a)
a=18.125

Is this correct?
 
Last edited:
Physics news on Phys.org
The solution is incorrect. wouldn't you suspect anything when the question gives so many variables and yet you only used half of them? :-p

First, what makes the object leave the floor?

Its the vertical force! So resolve everything in vertical form...
Force upward is equal force downward at point of leaving surface.

145sinθ=16sin(24.5)+8(9.8) <---assume gravity is 9.8

then you will get θ=35.9° (3 s.f)

Using the angle, you can find the acceleration, by resolving horizontal forces.
 

Similar threads

Replies
23
Views
3K
Replies
13
Views
3K
Replies
4
Views
2K
Replies
17
Views
2K
Replies
6
Views
3K
  • · Replies 21 ·
Replies
21
Views
8K
  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
4K
  • · Replies 24 ·
Replies
24
Views
4K