Can Static and Kinetic Friction Prevent a Car Crash?

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SUMMARY

The discussion focuses on the physics of friction in the context of a car braking scenario. Given a car mass of 1400 kg and an initial speed of 35 m/s, the required static friction to stop the car before hitting a wall 107 meters away is calculated to be 8014 N, while the maximum possible static friction is 6860 N. If the car slides, the coefficient of kinetic friction is 0.40, resulting in a collision speed of 19.6 m/s. Additionally, to navigate a circular path without crashing, the frictional force required is derived from the centripetal force equation.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction coefficients
  • Familiarity with equations of motion
  • Basic principles of circular motion
NEXT STEPS
  • Study the implications of static vs. kinetic friction in vehicle dynamics
  • Learn about the effects of weight distribution on braking performance
  • Explore the calculations involved in centripetal motion and frictional forces
  • Investigate advanced braking systems and their impact on stopping distances
USEFUL FOR

Physics students, automotive engineers, and anyone interested in vehicle safety and dynamics will benefit from this discussion.

mb218
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Homework Statement



Assume that the driver begins to brake the car when the distance to the wall is d=107m, and take the car's mass as m-1400kg, its initial speed as vo= 35m/s and the static coefficient to be .50. Assume that the car's weight is distributed evenly on the four wheels, even during braking.
a.) what magnitude of static friction is needed between the tires and road to stop the car just as it reaches the wall?
b.) what is the max possible static friction?
c.) if the coefficient of kinetic friction betweeen the sliding tires and the road is .40, at what speed will the car hit the wall.
d.) to avoid the crash, a driver could elect to turn the car so that it just barely misses the wall. What magnitude of frictional force would be required to keep the car in a circular path of radius d and at the given speed vo?
e.) is the required force that the maximum static friction so that a circular path is possible?



Homework Equations


N=mg
F=ma
v2=v initial-2ad


The Attempt at a Solution



a.)f=ma
f= 1400 x 5.724
f= 8014 N

b.) Fs max= usFn
=.5 x 1400 x 9.8
=6860

c.) ma= -ukmg
a=-.4 x 9.8
=-3.92

v2= 35^2+2x-3.92x107
v=19.6 m/s

d.)
mv^2/R= uk x N
N= 40070 N
 
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mb218 said:

Homework Statement



Assume that the driver begins to brake the car when the distance to the wall is d=107m, and take the car's mass as m-1400kg, its initial speed as vo= 35m/s and the static coefficient to be .50. Assume that the car's weight is distributed evenly on the four wheels, even during braking.
a.) what magnitude of static friction is needed between the tires and road to stop the car just as it reaches the wall?
b.) what is the max possible static friction?
c.) if the coefficient of kinetic friction betweeen the sliding tires and the road is .40, at what speed will the car hit the wall.
d.) to avoid the crash, a driver could elect to turn the car so that it just barely misses the wall. What magnitude of frictional force would be required to keep the car in a circular path of radius d and at the given speed vo?
e.) is the required force that the maximum static friction so that a circular path is possible?



Homework Equations


N=mg
F=ma
v2=v initial-2ad


The Attempt at a Solution



a.)f=ma
f= 1400 x 5.724
f= 8014 N

b.) Fs max= usFn
=.5 x 1400 x 9.8
=6860

c.) ma= -ukmg
a=-.4 x 9.8
=-3.92

v2= 35^2+2x-3.92x107
v=19.6 m/s
Your answers to a, b, and c look OK
d.)
mv^2/R= uk x N
N= 40070 N
If the car is to stay in a circle, it is not sliding..use the static friction coeficient... Don't solve for N, N is known...you are looking for the the friction force required to keep it in the circle (mv^2/r)...Since F_f (max)= u_s(N), can you answer part e?
 

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