Can Sub Lengths Be Equally Divided Among Three TAs?

  • Thread starter Thread starter remaan
  • Start date Start date
  • Tags Tags
    Hard
Click For Summary

Homework Help Overview

The problem involves dividing subs of varying lengths among three teaching assistants (TAs) such that each TA receives an equal total length. The lengths of the subs are represented by the integers from 1 to n, where n is a positive integer. The task is to determine for which values of n this equal division is possible.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss patterns observed in small values of n, questioning the feasibility of equal distribution. Some participants emphasize the importance of the total length formula, while others express concerns about the inability to break the subs into smaller pieces.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have provided insights into the total length calculation, while others are seeking further hints or guidance on proving their findings.

Contextual Notes

Participants note that the inability to break the subs is a critical constraint affecting the division process. There is also mention of specific values of n that have been tested for possible equal distribution.

remaan
Messages
132
Reaction score
0
Hard problem - dividing the subs !

Homework Statement



Anupam brought n > 0 subs, one each of length 1; 2; 3;... ; n, to a grading party.
The three TAs distributed the subs among themselves such that no sub was broken, and each TA
ended up with an equal total length. For what values of n is such a division possible?


Homework Equations


At some point, we may use the the sum formula : n(n+1)/2


The Attempt at a Solution



I tried finding a pattern

n = 1
we have only one sub, doesn't work

n= 2
doesn't work

n=3
doesn't work, as we can't divide this by 3 people.

n=4
doesn't work,

n= 5
it works !
we have 1,2,3,4,5
we can divide by 3 as follows :
one of the TAs will take 5
The other will take 4,1
The third will take 2,3

So, how should I precede with that ?

Do you think this is the right thing ?
 
Physics news on Phys.org


It's good that you looked for a pattern right off the start, but I think the main focus is in the formula they gave you (n(n+1)/2). This formula is the what you would use to find 1 + 2 + 3 +...+n. So in the context of this question (n(n + 1))/2 gives you the total length of bread that will be available.
Hope this helps.
 


Mmm...
Ya But the problem with that is:
Knowing how long bread I have Doesn't solve the problem, since
I Am not Able to break the breads apart.

So, any extra hints ??
 


Think about each bread as an integer. The fact that we can't break apart any bread when we divide the total length by 3 is important as it tells us something about the expression:
\frac{1}{3} \frac{n(n+1)}{2} , mainly that it can only take on values from a specific set.
Hope this helps
 
Last edited:


Ok. now suppose I found the two numbers -
are there any hints of how to prove them ?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 22 ·
Replies
22
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
12
Views
2K
Replies
23
Views
2K