Can the Binomial Theorem Prove This Series Equals (-2)^n?

AI Thread Summary
The discussion revolves around using the binomial theorem to prove that the series C(n,0) - 3C(n,1) + 9C(n,2) - 27C(n,3) + ... + (-3)^nC(n,n) equals (-2)^n. The user identifies that with b = -3 and a = 1, the expression can be rewritten as (-2)^n = (1 - 3)^n. They express uncertainty about whether mathematical induction is necessary for the proof and consider if writing the expression for (1+x)^n, with x = -3, suffices as proof. The user updates their approach by proving the base case for n=1 and assumes n=k, contemplating the need to prove n=k+1. The conversation emphasizes the connection between the binomial theorem and the series' evaluation.
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Use binomial theorem to prove

C(n,0) - 3(C(n,1)) + 9(C(n,2) - 27(C(n,3) + ... + (-3)^n(C(n,n) = (-2)^n


From looking at the data given b = (-3) so a = 1 so (-2)^n = (1-3)^n

With this I know the equation in sigma notation and could probably prove the theorem through mathematical induction but I'm not certain that is what they are looking for in this case...

Update:

I proved n=1 and assumed n = k, so do I need to prove n= k+1 through mathematical induction?
 
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Doesn't writing out the expression for (1+x)^n where x=-3 constitute proof?

edit: it's (1+x)^n
 
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