The discussion revolves around the applicability of the equation E = pc to particles, particularly focusing on whether it can be applied to particles with rest mass versus those without, such as photons.
The discussion is active, with participants providing insights and clarifications regarding the energy-momentum relationship and the implications of rest mass on the equation. There is an ongoing exploration of the mathematical relationships involved.
Participants are navigating through concepts of relativistic mass and energy, with some expressing uncertainty about the definitions and the implications of their evaluations. The original poster's assumptions about the applicability of the equation are being critically examined.
Just a clarification of what gleem is saying:gleem said:where of course mc2 = E
OK. Now substitute ##E=\gamma m_0 c^2## for E. What does this reduce to? Do you know the relativistic momentum expression?andrevdh said:I get up to the point where it evaluates to E2(v2/c2)?
It is relevant because you just derived the forumula ##pc=\sqrt{{\gamma}^2m_0^2 c^4 - m_0 ^2c^4} = \sqrt{E^2-m_0^2 c^4}##, proving the fact that ##E≠pc## if ##m_0 ≠0 ##, which I believe was your original question.andrevdh said:I think it comes to (pc)2?
Which approaches the energy-momentum relation from the other side.
How is this relevant to the original question?
We evaluated a difference between two terms and found
that they are related to the relativistic momentum of the entity?