- #1
jeff91
- 2
- 0
Is it possible to rearrange or inverse this to solve for p(1X | Y)? I haven't done this level of maths for over 15 years and haven't a clue where to start.
1wk =p(1X | Y)⋅ wk
weight vector of 1X node in case a is 1w=[1w1, 1w2,…, 1wm]
weight vector of Y node w=[w1, w2,…, wm]
where 1 ≤ k ≤ m
1wk =p(1X | Y)⋅ wk
weight vector of 1X node in case a is 1w=[1w1, 1w2,…, 1wm]
weight vector of Y node w=[w1, w2,…, wm]
where 1 ≤ k ≤ m