- #1

jeff91

- 2

- 0

_{1}X | Y)? I haven't done this level of maths for over 15 years and haven't a clue where to start.

_{1}w

_{k}=p(

_{1}X | Y)⋅ w

_{k}

weight vector of

_{1}X node in case a is

_{1}w=[

_{1}w

_{1},

_{1}w

_{2},…,

_{1}w

_{m}]

weight vector of Y node w=[w

_{1}, w

_{2},…, w

_{m}]

where 1 ≤ k ≤ m