Can this in any way be considered to be a circularly polarized wave?

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The discussion centers on whether a given wave can be classified as circularly polarized. One participant argues against it, stating that there is no twisting along the direction of propagation, while their friend contends that the phase shift in the y-axis indicates circular polarization. The latter clarifies that the wave exhibits circular motion over time, which qualifies it as circularly polarized. Additionally, it is noted that the expression represents a standing wave rather than a propagating one, and the characteristics of left and right circularly polarized waves are explained. Ultimately, the conversation highlights the nuances of wave polarization and the importance of phase relationships in determining wave properties.
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Can this in any way be considered a circularly polarized wave?

Can this wave in any way be considered circularly polarized?

\overrightarrow {E}\left( z,t\right) =\left[\widehat {i}\cos \left( \omega t\right) +\widehat {j}\cos \left( wt-\dfrac {\pi } {2}\right)\right] E_{0}\sin \left( kz\right)

I say no, since there is no twisting along the direction of propagation. If you plug in t=0 for instance, the vectors will be pointing entirely in the x-axis direction.

My friend disagrees and mentions the phase shift in the y-axis as evidence for circular polarization.
 
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DocZaius said:
Can this wave in any way be considered circularly polarized?

\overrightarrow {E}\left( z,t\right) =\left[\widehat {i}\cos \left( \omega t\right) +\widehat {j}\cos \left( wt-\dfrac {\pi } {2}\right)\right] E_{0}\sin \left( kz\right)

I say no, since there is no twisting along the direction of propagation. If you plug in t=0 for instance, the vectors will be pointing entirely in the x-axis direction.

My friend disagrees and mentions the phase shift in the y-axis as evidence for circular polarization.
Your friend is right - at any z location, field is circulating in direction with time. And that means a CP (circularly polarized) wave. You appear to be confusing CP with corkscrew motion that would apply to propagation down a twisted waveguide.
 
Thanks for the quick reply!
 
DocZaius said:
Thanks for the quick reply!
You're welcome - I just happened to be viewing at the time and felt the impulse to respond! :smile:
 
I should add that your expression in #1 represents a standing wave CP (sum of two counter-propagating CP waves of opposite CP polarization) not propagating one. For a single propagating CP wave, the sin(kz) term is absent and the cos(ωt), cos(ωt-π/2) arguments are replaced with cos(ωt-kz-θ), cos(ωt-π/2-kz-θ) respectively, with θ determined by the given t=0 temporal phase conditions at z=0. That may represent a LCP wave (left circularly polarized) - counterclockwise rotation of field as viewed along propagation axis with wave receding. For a RCP wave, an extra phase angle of π is added to either one, but not both, of the above arguments for cos. Convention for handedness can vary, but I believe above is the more standard one.
 
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