Can Triple Integrals Be Simplified Using Polar Spherical Coordinates?

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SUMMARY

The discussion centers on the simplification of triple integrals using polar spherical coordinates, specifically addressing the integral \int_{R^{3}}d^{3}r F( \vec r . \vec r , \vec r . \vec a , |r| ,|a|). It is established that the function F is invariant under rotation and translation due to its dependence on the scalar product of vector r=(x,y,z) and its modulus |r|. The integral can indeed be transformed into the form \int d\Omega \int_{0}^{\infty}k^{2}F(k)dk, where k=|r|, confirming the feasibility of this simplification.

PREREQUISITES
  • Understanding of triple integrals and their properties
  • Familiarity with polar spherical coordinates
  • Knowledge of scalar products in vector calculus
  • Basic concepts of invariance under transformations
NEXT STEPS
  • Study the application of polar spherical coordinates in multiple integrals
  • Learn about the properties of scalar products in vector analysis
  • Explore the concept of invariance in mathematical transformations
  • Investigate advanced integration techniques in multivariable calculus
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Mathematicians, physicists, and students studying multivariable calculus who are interested in simplifying complex integrals using polar spherical coordinates.

mhill
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let be the integral

[tex]\int_{R^{3}}d^{3}r F( \vec r . \vec r , \vec r . \vec a , |r| ,|a|)[/tex] (1)

F depends only on the scalar product of vector r=(x,y,z) and its modulus |r| , hence it is invariant under rotation and traslations (since scalar product is invariant under rotation and traslation) my question is if using polar spherical coordinates we can put the integral (1)

as [tex]\int d\Omega \int_{0}^{\infty}k^{2}F(k)dk[/tex] being k=|r| (modulus of r)

i believe answer is affirmative
 
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mhill said:
let be the integral

[tex]\int_{R^{3}}d^{3}r F( \vec r . \vec r , \vec r . \vec a , |r| ,|a|)[/tex] (1)

F depends only on the scalar product of vector r=(x,y,z) and its modulus |r| , hence it is invariant under rotation and traslations (since scalar product is invariant under rotation and traslation) my question is if using polar spherical coordinates we can put the integral (1)

as [tex]\int d\Omega \int_{0}^{\infty}k^{2}F(k)dk[/tex] being k=|r| (modulus of r)

i believe answer is affirmative

Your assumption is correct. I suspect your original statement refers to a scalar product of r and a. Also I assume a is a constant vector.
 

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