Can We Define Acceleration for Speed Using Average Acceleration Formula?

  • Context: High School 
  • Thread starter Thread starter phymatter
  • Start date Start date
  • Tags Tags
    Acceleration Vector
Click For Summary
SUMMARY

The discussion clarifies that acceleration can indeed be defined for speed using the average acceleration formula, specifically through the concept of tangential acceleration. Tangential acceleration is the component of acceleration that points in the same direction as the velocity and is calculated as the derivative of speed with respect to time. The conversation also highlights the relationship between tangential and centripetal acceleration, emphasizing that the total acceleration of a particle can be expressed as the sum of these two components. This understanding is crucial for analyzing motion in non-uniform circular paths.

PREREQUISITES
  • Understanding of basic physics concepts, specifically velocity and acceleration.
  • Familiarity with vector mathematics and differential geometry.
  • Knowledge of the relationship between speed, direction, and acceleration.
  • Basic grasp of centripetal acceleration and its formula v²/r.
NEXT STEPS
  • Study the concept of tangential acceleration in more detail.
  • Learn about centripetal acceleration and its applications in circular motion.
  • Explore differential geometry and its relevance to motion analysis.
  • Investigate the mathematical derivation of acceleration components in various motion scenarios.
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in the mathematical foundations of motion and acceleration analysis.

phymatter
Messages
131
Reaction score
0
just got a bit confused : because acceleration is a vector , so can we define acceleration for speed , that is , if we say speed at t1 is a , t2 is b , then average acceleraion is (b-a)/(t2-t1) pl. help !
 
Physics news on Phys.org


Yes; the quantity you're interested in is called "tangential acceleration."

And now for a more thorough answer than you wanted:
Velocity is a vector, so it has both a magnitude and a direction. (The magnitude of the velocity is called "speed," as you are already aware.) Acceleration is a change in velocity. Thus if either the speed or the direction of a velocity changes, an acceleration is taking place.

There's a theorem in differential geometry which says that a particle's acceleration vector can always be expressed as the sum of two vectors, called the tangential acceleration and the centripetal acceleration. Furthermore, the tangential acceleration points in the same direction as the velocity (where "same direction" includes the possibility of pointing exactly backwards, for a decelerating particle) and has a magnitude equal to the derivative of speed with respect to time, and the normal acceleration always points perpendicular to the particle's path (unless it's zero) and has a magnitude equal to the particle's instantaneous speed squared over the radius of curvature of the particle's path.

This theorem is a big deal because the magnitude of the centripetal acceleration, when written in symbols, is v^2/r. You should remember that as the formula for centripetal acceleration when a particle moves in a circle with a constant speed. What this theorem says is that if a particle *isn't* moving in a circle with constant speed, then at any instant in time you can still approximate it as a particle moving in some circle but with a changing speed, and then its acceleration is the same old centripetal acceleration PLUS a tangential acceleration corresponding to the change in speed.

This fact is a lot more exciting when it's written as an equation, but you need three or four different equations to define all of the symbols that show up.
 


thanks Penn.6-5000 !
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K