Can we prove that x>1 implies y<1 if 3x+2y≤5 for real numbers x and y?

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Discussion Overview

The discussion revolves around the relationship between the variables x and y under the constraint 3x + 2y ≤ 5. Participants explore whether the condition x > 1 implies y < 1, examining the implications of these inequalities.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant proposes that if x > 1, then y must be less than 1, based on the given inequality.
  • Another participant questions the scenario where both x > 1 and y ≥ 1 could be true, implying a potential contradiction.
  • A third participant expresses uncertainty about the implications of the conditions presented.
  • One participant critiques the manner in which help is requested, suggesting it does not fit the forum's guidelines.

Areas of Agreement / Disagreement

Participants do not reach a consensus, as there are competing views regarding the implications of the inequalities and the appropriateness of the discussion format.

Contextual Notes

There are unresolved assumptions regarding the definitions of the variables and the implications of the inequalities presented.

bean29
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Suppose x and y are real numbers and 3x+2y≤5. Prove that if x>1 then y<1
 
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What would happen if x &gt; 1 and y \ge 1 were both true?
 
Not real sure what would happen.
 
This is not an acceptable way to ask for help at homework problems. In addition, it is in the wrong forum.
 

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