RTCNTC said:Is the following correct?
MarkFL said:You're actually missing two roots of the equation:
$$x^3=\sqrt{81}$$
Write as difference of cubes:
$$x^3-\left(3^{\frac{2}{3}}\right)^3=0$$
Factor:
$$\left(x-3^{\frac{2}{3}}\right)\left(x^2+3^{\frac{2}{3}}x+3^{\frac{4}{3}}\right)=0$$
The quadratic factor will yield the two complex conjugate roots. ;)
RTCNTC said:What do you think of MathMagic Lite? Cool, right?
RTCNTC said:1. Are you saying that my answer is wrong?
RTCNTC said:2. How badly was your area hit by Irma?