Can You Derive Equations Using UAM Principles?

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Homework Help Overview

The original poster seeks to derive specific equations related to uniformly accelerated motion (UAM) principles, specifically equations 5-1 and 5-2. The context involves understanding the relationships between variables in projectile motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using standard constant acceleration equations for both horizontal and vertical motion separately. The original poster expresses uncertainty about where to begin and mentions previous success with other equations.

Discussion Status

Some participants have offered guidance on focusing on the basic equations of motion and suggested showing their work. There is an ongoing exploration of how to apply these equations to derive the desired results, with no clear consensus yet.

Contextual Notes

The original poster is new to physics and is navigating the complexities of deriving equations without relying on memorized formulas. There is an emphasis on understanding the underlying principles rather than simply applying known equations.

jensgt
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Homework Statement


Can you come up with (i.e. derive) equations 5-1 and 5-2 on your own using UAM equations? Try it


Homework Equations



This is the equation I need to end up at...

R=Vox/g(Voy+(Voy^+2gh)^1/2


The Attempt at a Solution



I am not really sure where to start. I was trying to use the equations for range and height but it does not seem to be getting me anywhere. This is my first physics course.
 
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welcome to pf!

hi jensgt! welcome to pf! :smile:

(try using the X2 button just above the Reply box :wink:)

don't try to memorise (or use) the range or height equations :wink:, go back to the standard constant acceleration equations, for the x and y directions (separately)

they'll use the same t …

show us what you get :smile:
 
The equations I know are

Vx = Vox + Axt

X = Xo + Voxt + 1/2axt^2

X-Xo = [(Vox + Vx)/2]t

Vx^2 = Vox^2 +2ax(X-Xo)

I am just confused as to where to start. I derived the other one he asked us about this one has me stuck.
 
hi jensgt! :smile:

(just got up :zzz:)
jensgt said:
I am just confused as to where to start.

use x = xo + Vxot + 1/2axt2

and y = yo + Vyot + 1/2ayt2

(obviously, ax = 0) …

show us what you get :smile:

(btw, never use "x" for times, it's too confusing … use "*" instead, or nothing at all! :wink:)
 

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