A dog jumps a distance, L, and a maximum height, H, where the dog only has horizontal velocity when it travels through the hoop. What is the speed of your dog when he leaves the ground?
What is the speed of your dog when he goes through the loop? Both answers should NOT be in terms of sinθ or cosθ.
Max height = H
Distance = L
V at max height = Vx
V^2 = Vo^2 + 2gΔH
V = (Vox^2+Voy^2)^.5
The Attempt at a Solution
0 = Voy^2 +2gH
Voy = square root(2gH)
My problem is I do not know how to find the horizontal component of velocity in order to solve the rest of the problem. I would greatly appreciate any help.
ps sorry for the bad formatting, this is my first time one the site.