Can You Determine the Gradient of an Unknown Function?

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SUMMARY

The forum discussion centers on Mubashir's attempt to determine the gradient of an unknown function without traditional differentiation methods. He proposes a formula involving trigonometric functions and secant lines, specifically using the equation dy/dx = 10^10*tan(½(tan-1((f(x+1)–f(x))/10^10)+tan-1((f(x)–f(x-1))/10^10))). However, other participants point out that his method is fundamentally flawed, as it relies on averaging angles rather than directly calculating slopes, leading to inaccuracies. The consensus is that traditional differentiation methods yield more precise results, especially for polynomial functions.

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  • Understanding of basic calculus concepts, particularly derivatives and limits.
  • Familiarity with trigonometric functions and their properties.
  • Knowledge of secant and tangent lines in the context of curve analysis.
  • Ability to perform calculations involving limits and approximations.
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  • Study the concept of limits in calculus to understand the foundation of differentiation.
  • Learn about the properties of secant and tangent lines in calculus.
  • Explore the relationship between derivatives and approximations in numerical methods.
  • Investigate the use of trigonometric functions in calculus and their applications in gradient calculations.
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Students of calculus, mathematicians, and anyone interested in understanding alternative methods for calculating derivatives and their limitations.

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  • #31
Well, We do know the height, but we don't have any type of polynomial ruling the motion... That was what I meant, using the word function was a mistake :)
I'm sorry
 
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  • #32
mubashirmansoor said:
Well, We do know the height

Yep, that's what I mean. You have to be able to compute (or measure off of a graph, or something) f(x+\Delta x ) and f(x-\Delta x) in order to use those approximations.
 
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