Can you find diffrent ball by three times?

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The discussion revolves around a classic puzzle involving 12 balls, where one ball is either lighter or heavier than the others. The challenge is to identify the different ball and determine its weight difference using a balance scale in three weighings. Participants acknowledge the puzzle's historical significance in mathematics and its presence in various forms of media, such as the "Zork" computer game. The conversation highlights the cleverness required to solve the puzzle rather than focusing solely on mathematical skills. Despite the engaging nature of the topic, there is some frustration regarding the lack of responses and clarity in the discussion.
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There are 12 balls, including a ball with other balls, it is lighter or heavier than others, can you use a Balance without weights to find out the different ball Up to three times?
 
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Unfortunately, I'm not sure if this is really for "General Math," this is a pretty well-known puzzle, and relies on one's general cleverness as opposed to one's mathematical cleverness.

Probably a better translation would be (no offence):

"Suppose you have three balls, one of which is either lighter or heavier than the others. With a balance-based scale, is it possible to determine which ball is the one with a different weight, and whether it's heavier or lighter, in three balances?"
 
there are twelve balls,but one of them is different.
Different is its weight
 
can you find the different one ?
Only one way
 
You have now posted 7 times in this one thread with only two responses. Yes, Chinese mathematics has a long and noble heritage. And determining which of a set of balls, or coins, weight more or less than the others is an old, traditional puzzle (it even appears in one of the old "Zork" computer games by Infocom). But what is your point?
 
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